5 + 11
11 + 5
7 + 9
9 + 7
So 4 ways if you are allowed to throw each die only once. But the question did not state that assumption; so the additional ways are:
Throw die #1 16 times and get 1 each time.
Throw die #2 16 times and get 1 each time.
Throw die # 1 13 times and get 1 13 times and 3 once.
Throw die # 2 13 times and get 1 13 times and 3 once.
Throw die #1 13 times and get 1 each time, then throw die # 2 once and get 3.
Throw die #1 12 times and get 1 each time, then throw die #2 once and get 3, then throw die #1 again and get another 1.
You get the idea, figure out the rest yourself.
There are only three possible solutions... 1 & 11, 3 & 9 or 5 & 7
Close to 360
It depends on what numbers are on the faces of the tetrahedral dice. The answer can be any number between 1 and 8. If each face of the two tetrahedorns is 1, the total is always two and so there is only one answer. If the faces of the two tetrahedrons are numbered 1,2,4,and 8 the sum will be one of eight possible numbers.
1/9
A die (if someone says "dice", that is the plural).
All the numbers on the dice are odd. Therefore no matter what the rolls are, you will always get two odd numbers. Two odd numbers added together always equal an even number. However, the requested total is 11, an odd number. This is clearly impossible, and so we can say there are no ways of scoring a total of 11.
Assuming they are fair dice that are numbered 1 to 6, the probability is 2/36 = 1/18
There are only three possible solutions... 1 & 11, 3 & 9 or 5 & 7
numbered cube = Dice buyme24buyme.com
Close to 360
There are 3 odd numbers since there are a total of 6 consecutive numbers on a dice. For example, the numbers 1 2 3 4 5 6 are on a dice, so the odd numbers are 1, 3, and 5.
It depends on what numbers are on the faces of the tetrahedral dice. The answer can be any number between 1 and 8. If each face of the two tetrahedorns is 1, the total is always two and so there is only one answer. If the faces of the two tetrahedrons are numbered 1,2,4,and 8 the sum will be one of eight possible numbers.
Probability is 1/8 or 0.125 or 12.5% Explanation: A fair dice with six sides (numbers) has a probability of 1/2 of rolling an even number. Note: 1/2 = 3/6, where the dice has 3 even numbers out of six total sides. The probability of three same dice all roll an even number is the probability of one of these (1/2) to the power 3, or (1/2) * (1/2) * (1/2) which equals 1/8.
1/9
3
A die (if someone says "dice", that is the plural).
1:6