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It is 1/2 if it is a fair number cube which is rolled once.
There are 6 numbers on a die. Therefore there are 6 possible numbers that can be rolled. "3" is one of those numbers. The odds are therefore 1/6.
The question depends on what the numbers are being rolled on: a hexahedron or some other shape.
It is no big deal. You could do that if the die was not the standard cube with numbers 1 to 6.
There is a 1/2 chance of rolling an odd number on either die, so 1/2 X 1/2 = 1/4. 1/4 is the probability that both die will have odd numbers, so 3/4 is the probability that at least one is even.
The probability that the sum of the numbers rolled is either even or a multiple of 5 is 11/18.
1.00 or 100%. Look at the possible outcomes: 1, 2, 3, 4, 5, 6. In this range, what are the even numbers: 2, 4, 6. What are the odd: 1, 3, 5. So the set of (even or odd) numbers is the union of odd numbers and even numbers. This is the same as the set of possible outcomes. Therefore it will happen, so 100 percent chance (or 1.00)
It is 1/2 if it is a fair number cube which is rolled once.
There are 6 numbers on a die. Therefore there are 6 possible numbers that can be rolled. "3" is one of those numbers. The odds are therefore 1/6.
The most likely number to be rolled in craps is the number 7
The question depends on what the numbers are being rolled on: a hexahedron or some other shape.
It is no big deal. You could do that if the die was not the standard cube with numbers 1 to 6.
Number of possible outcomes = 6Number of outcomes that are odd numbers = 3P = 3/6 = 50% .
7
There is a 1/2 chance of rolling an odd number on either die, so 1/2 X 1/2 = 1/4. 1/4 is the probability that both die will have odd numbers, so 3/4 is the probability that at least one is even.
Any number between 2 and 12.1+16+6
1/6 because the other numbers don't affect the probability