It is 1/2 if it is a fair number cube which is rolled once.
It is 0.722... recurring.
The answer depends on how many times it is rolled.
For most people the probability is 1: they have already rolled a number cube. For infants, it is quite likely to happen in the course of their lives, so again the probability is very close to 1.
On a normal cube, the probability is 0. If there are more than 1 cubes, the answer depends on how many are being rolled for each sum.
It is no big deal. You could do that if the die was not the standard cube with numbers 1 to 6.
7
it depends on how many numbers are on the number cube. if it only goes to 6, then the probability is 1/6. if it goes to 8 then the probability is 2/8. and so on and so on...
It means that there is a serious error in your calculations since a probability cannot ever be greater than 1.
It is 0.722... recurring.
The answer depends on how many times it is rolled.
If a standard number cube or die is rolled, the probability that a 4 does not land face up is five out of six, or (six minus one) out of six.
For most people the probability is 1: they have already rolled a number cube. For infants, it is quite likely to happen in the course of their lives, so again the probability is very close to 1.
A number cube is a six sided figure so I'm going to go with 0%
It is 1/2.
Because 3/6 of the sides on a number cube have even numbers, the probability of rolling even on one number cube is 1/2(equivalent of 3/6). But since you're rolling twice, you multiply the probability of one by itself (therefore rolling 2 number cubes). So: 1/2x1/2=1/4 The probability of rolling an even number when a number cube is rolled twice is 1/4, 25%, or 1 out of 4.
These are all independent events. So the probability of them all happening is the product of the probabilities of each one of them happening. The desired probability is (2/6)*(1/2)*(1/2)=1/12
It is approx 0.99989, that is, a near certainty.