It is 1/2 if it is a fair number cube which is rolled once.
It is 0.722... recurring.
The answer depends on how many times it is rolled.
For most people the probability is 1: they have already rolled a number cube. For infants, it is quite likely to happen in the course of their lives, so again the probability is very close to 1.
A standard number cube, or die, has six faces numbered from 1 to 6. Since there are no numbers greater than 7 on a standard die, the probability of rolling a number greater than 7 is 0. Therefore, the probability is 0%.
On a normal cube, the probability is 0. If there are more than 1 cubes, the answer depends on how many are being rolled for each sum.
7
it depends on how many numbers are on the number cube. if it only goes to 6, then the probability is 1/6. if it goes to 8 then the probability is 2/8. and so on and so on...
It means that there is a serious error in your calculations since a probability cannot ever be greater than 1.
It is 0.722... recurring.
The answer depends on how many times it is rolled.
If a standard number cube or die is rolled, the probability that a 4 does not land face up is five out of six, or (six minus one) out of six.
For most people the probability is 1: they have already rolled a number cube. For infants, it is quite likely to happen in the course of their lives, so again the probability is very close to 1.
A number cube is a six sided figure so I'm going to go with 0%
A standard number cube, or die, has six faces numbered from 1 to 6. Since there are no numbers greater than 7 on a standard die, the probability of rolling a number greater than 7 is 0. Therefore, the probability is 0%.
Because 3/6 of the sides on a number cube have even numbers, the probability of rolling even on one number cube is 1/2(equivalent of 3/6). But since you're rolling twice, you multiply the probability of one by itself (therefore rolling 2 number cubes). So: 1/2x1/2=1/4 The probability of rolling an even number when a number cube is rolled twice is 1/4, 25%, or 1 out of 4.
It is 1/2.
These are all independent events. So the probability of them all happening is the product of the probabilities of each one of them happening. The desired probability is (2/6)*(1/2)*(1/2)=1/12