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Two persons A and B starts running a certain distance at 8 and 10 kmph respectively B reaches the destination 6 mins earlier what is the distance?
Rinzinlhamo
let the distanncccee covered by both be 'S' km.
And time taken by A be 'x' min..
therefore time taken by B is 'x+6' min.
8x=(x+6)10
8x=10x+60
-2x=60
x=-60/2
x=-30
distance can not be negetive, so
x=30
i.e, distance travelled is 30 km.
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