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let the distanncccee covered by both be 'S' km.

And time taken by A be 'x' min..

therefore time taken by B is 'x+6' min.

8x=(x+6)10

8x=10x+60

-2x=60

x=-60/2

x=-30

distance can not be negetive, so

x=30

i.e, distance travelled is 30 km.

Q: Two persons A and B starts running a certain distance at 8 and 10 kmph respectively B reaches the destination 6 mins earlier what is the distance?

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