earlier for two options (which is actually one option!), earliest for more than two options.
Probably it was the ancient Babylonians whose number base was 60 or maybe the ancient Mayans whose number base was 20
113 is not a complex number and so there cannot be any correct notation.
you put a dash where the correct number is.
Yes, that is correct.
In a multiple-choice test with 4 options (a, b, c, d) for each question, the probability of guessing correctly for each question is ( \frac{1}{4} ). If a student guesses on 10 questions, the expected number of correct guesses can be calculated by multiplying the number of questions by the probability of a correct guess: ( 10 \times \frac{1}{4} = 2.5 ). Therefore, the mean expected correct guesses for the student is 2.5.
I need the same answer LOL
If we just include natural numbers; i.e. integers greater than or equal to zero, then one thousand (1,000) would be the lowest (earliest) number with the letter a in it.
Correct! There is no bigist number. There is no biggest number either.
No. See the Related Link.
Divide the number correct by the total possible.
A person will not be able to know which answer lists the correct number of bits without knowing what the answer choices are. In order to know which of the answers is correct the answer options should be given.
I don't think they did.
The phone number of the Positive Options is: 616-241-5554.
Go to Settings > Options > Phone options > General Options > Restrict my identity
The correct American Express number format is a 15-digit number starting with 3.
With the numbers: 0,1,2,3,4,5,6,7,8,9 there are 10000 four letter combination's - ten options for the first number times ten options for the second number times ten options for the third number and so on. :)
Since there are only two options for the answer, on average the student will answer half of the answers correctly.