Let the number be 'n' & 'n+1'
Hernce there product is
n(n+1) = 210
Multiply out the brackets
n^2 + n = 210
n^2 + n - 210 = 0
It is now in quadratic form ; apply the Quadratic Eq'n
n = { -1 +/- sqrt[ 1^2 - 4(1)(-210)]} / 2(1)
n = { -1 +/- sqrt[ 1 + 840]} / 2
n = {-1 +/- sqrt(841]} / 1
n = { - 1 +/- 29]} / 2
n = 28/ 2 = 14
n - -30/2 = -15 (Not required positive answer only).
Hence n = 14 & n+ 1 = 15 are the two positive integers.
The numbers are 8 and 9.
The product of two integers cannot be "positive and negative".
The two consecutive, odd integers whose product equals 143 are 11 and 13.
13 & 15
13 x 15 = 195
There are no two consecutive integers, negative or positive, whose product is 440.
the two consecutive positive integers whose product is 380 19 20
There are no two consecutive integers whose product is 421 - the product of 20 and 21 is 420.
The numbers are 8 and 9.
99 = 9*11
There are two consecutive odd integers whose sum is 340. They are 169 and 171.
Well, darling, if you're looking for the product of two consecutive integers that equals 380, then you're in luck. The two integers are 19 and 20. See, no need to break a sweat over this math riddle. Just keep on strutting your stuff!
The product of two integers cannot be "positive and negative".
The two consecutive, odd integers whose product equals 143 are 11 and 13.
26 and 28
13 & 15
13 * 15