answersLogoWhite

0

Let the number be 'n' & 'n+1'

Hernce there product is

n(n+1) = 210

Multiply out the brackets

n^2 + n = 210

n^2 + n - 210 = 0

It is now in quadratic form ; apply the Quadratic Eq'n

n = { -1 +/- sqrt[ 1^2 - 4(1)(-210)]} / 2(1)

n = { -1 +/- sqrt[ 1 + 840]} / 2

n = {-1 +/- sqrt(841]} / 1

n = { - 1 +/- 29]} / 2

n = 28/ 2 = 14

n - -30/2 = -15 (Not required positive answer only).

Hence n = 14 & n+ 1 = 15 are the two positive integers.

User Avatar

lenpollock

Lvl 16
1y ago

Still curious? Ask our experts.

Chat with our AI personalities

FranFran
I've made my fair share of mistakes, and if I can help you avoid a few, I'd sure like to try.
Chat with Fran
CoachCoach
Success isn't just about winning—it's about vision, patience, and playing the long game.
Chat with Coach
ProfessorProfessor
I will give you the most educated answer.
Chat with Professor
More answers

14 & 15. They are positive (greater than zero), consecutive (one right after the other) and when you multiply them together the answer/product is 210.

User Avatar

Wiki User

16y ago
User Avatar

Add your answer:

Earn +20 pts
Q: Two positive consecutive integers whose product is 210?
Write your answer...
Submit
Still have questions?
magnify glass
imp