Best Answer

Let the number be 'n' & 'n+1'

Hernce there product is

n(n+1) = 210

Multiply out the brackets

n^2 + n = 210

n^2 + n - 210 = 0

It is now in quadratic form ; apply the Quadratic Eq'n

n = { -1 +/- sqrt[ 1^2 - 4(1)(-210)]} / 2(1)

n = { -1 +/- sqrt[ 1 + 840]} / 2

n = {-1 +/- sqrt(841]} / 1

n = { - 1 +/- 29]} / 2

n = 28/ 2 = 14

n - -30/2 = -15 (Not required positive answer only).

Hence n = **14** & n+ 1 =

Q: Two positive consecutive integers whose product is 210?

Write your answer...

Submit

Still have questions?

Continue Learning about Math & Arithmetic

The numbers are 8 and 9.

The product of two integers cannot be "positive and negative".

The two consecutive, odd integers whose product equals 143 are 11 and 13.

13 & 15

13 x 15 = 195

Related questions

The two consecutive positive integers whose product is 380 are 19 x 20.

There are no two consecutive integers, negative or positive, whose product is 440.

the two consecutive positive integers whose product is 380 19 20

There are no two consecutive integers whose product is 421 - the product of 20 and 21 is 420.

The numbers are 8 and 9.

99 = 9*11

There are two consecutive odd integers whose sum is 340. They are 169 and 171.

The product of two integers cannot be "positive and negative".

The two consecutive, odd integers whose product equals 143 are 11 and 13.

They are: 40*41 = 1640

26 and 28

They are are 7 and 8.