The whole question is Two vertical poles of height 1 yard and 2 yards are located 3 yards apart. The poles are secured by the rope going from the top of one pole to a poing on the ground between the poles and then to the top of the second pole. Where should the point on the ground be located to minimize the length of the rope. What is the minimal leght of the rope?
Can someone please help
two vertical poles of equal height stand on either of a roadway wich is 20 ft wide. At a point in the roadway b/n the poles, the elevation of the taps of the poles are 30 degree and 60 degree. Find the height of the poles?
No. All of the meridians merge in a single point at the poles.
"Like chalk and cheese" is a common, and pretty obvious one (you couldn't really substitute one for the other)..really means "not alike" rather than opposite. "Poles apart" is another, as in "the two footballers are poles apart in terms of fitness"...it comes from the North & South poles at opposite ends of the earth.
1 mile = 320 poles.
1 acre is 160 square poles.
10 feet
two vertical poles of equal height stand on either of a roadway wich is 20 ft wide. At a point in the roadway b/n the poles, the elevation of the taps of the poles are 30 degree and 60 degree. Find the height of the poles?
Poles Apart was created in 1994.
It has been awhile for me, but if all of the poles are to the left of the vertical axis, then it will be stable. Any poles on the vertical, or to the right, and it will be unstable.
quadrangle includes 6 poles. 2 timing poles and 4 poles that you actually turn. the four poles that you turn are each 75 feet apart from each other forming a square. the timing poles are directly in the center of the square and are 30 feet apart from each other.
Vertical Ascent tent style 35861 H99 B09 35861 CedarBreaks replacement poles
For this particular problem, the point of intersection is 4 feet above the ground.The general formula for this situation is as follows:Let h=height of the shorter poleLet H=height of the taller poleThen the height of the point of intersection, let's call it y, will bey = (hH)/(h+H) or more symmetrically, 1/y = 1/h + 1/HThis may be deduced by simple algebra and the comparison of sides of similar triangles.An interesting aspect of this problem is that the distance between the poles does not appear anywhere in the solution! No matter how far apart you stretch the poles, the height of the point of crossing remains the same - it just slides along a horizontal line at the calculated height.Another point of interest is that the ratio of the horizontal distance from one pole to the crossing point ( call it x ) divided by the total distance between the two poles ( call it D ) also remains the same as the poles are moved apart. Specifically,(x/D) = H/(h+H) = (a constant for a fixed set of poles)
21 feet apart
Trees and mountains have vertical edges, as do buildings and telephone poles.
Lines of constant latitude don't cross the equator. Any two lines of constant longitude are farthest apart at the equator, and meet at the north and south poles.
Poles Apart - 2000 was released on: USA: 8 July 2000 (Los Angeles Outfest Gay and Lesbian Film Festival)
No. All of the meridians merge in a single point at the poles.