y = 2x2 - 3x - 1 = 0 After graphing this equation on my calculator, I found that there are in fact two answers, but neither of them are integers. This means that it is impossible to factor this quadratic equation in the form (x + a)(x + b) with a and b being integers.
This quadratic equation has no solutions because the discriminant is less than zero.
(x - 16)(x + 4) = 0 so x = -4 or 16
Expression: x^2 -x -12 Completing the square: (x -0.5)^2 -12.25
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It cannot be solved because the discriminant of the quadratic equation is less than zero
This quadratic equation has no solutions because the discriminant is less than zero.
(x - 16)(x + 4) = 0 so x = -4 or 16
Expression: x^2 -x -12 Completing the square: (x -0.5)^2 -12.25
There is a formula for "the difference of squares." (x + 7)(x - 7) = 0 x = 7, -7
Please do not remove this question from Inappropriate or split any alts from it. Thanks!
It cannot be solved because the discriminant of the quadratic equation is less than zero
By running on bases
Divide all terms by 3 so:- x2-4x = 5 Completing the square:- (x-2)2 = 9 x-2 = -/+3 x = -1 or x = 5
by doing nooki
By completing the challenge it says on it.
How do you solve 4y plus x equals 8
121 is the answer