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y = 2x2 - 3x - 1 = 0 After graphing this equation on my calculator, I found that there are in fact two answers, but neither of them are integers. This means that it is impossible to factor this quadratic equation in the form (x + a)(x + b) with a and b being integers.
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Solve by completing square 2x² - 6x plus 7 equals 0?
This quadratic equation has no solutions because the discriminant is less than zero.
How do you solve x squared minus x minus 12by completing squares?
Expression: x^2 -x -12 Completing the square: (x -0.5)^2 -12.25
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Please do not remove this question from Inappropriate or split any alts from it. Thanks!
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It cannot be solved because the discriminant of the quadratic equation is less than zero
Solve by completing square 2x² - 6x plus 7 equals 0?
This quadratic equation has no solutions because the discriminant is less than zero.
How do you solve x squared minus x minus 12by completing squares?
Expression: x^2 -x -12 Completing the square: (x -0.5)^2 -12.25
Solve the quadratic equation x squares -12x-64 equals 0?
(x - 16)(x + 4) = 0 so x = -4 or 16
How do you solve 8x2 plus 14x plus 5 equals 0 by completing the square?
Please do not remove this question from Inappropriate or split any alts from it. Thanks!
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by doing nooki
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I couldn't answer the question because the question is not proper to slove. I just want you to follow the related link that explains how to solve the equation by completing the square.
How do you solve 4y plus x equals 8?
How do you solve 4y plus x equals 8
