y = 2x2 - 3x - 1 = 0 After graphing this equation on my calculator, I found that there are in fact two answers, but neither of them are integers. This means that it is impossible to factor this quadratic equation in the form (x + a)(x + b) with a and b being integers.
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This quadratic equation has no solutions because the discriminant is less than zero.
(x - 16)(x + 4) = 0 so x = -4 or 16
Expression: x^2 -x -12 Completing the square: (x -0.5)^2 -12.25
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It cannot be solved because the discriminant of the quadratic equation is less than zero