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x2 + 2x + 5 = 0 is already in the form ax2 + bx + c = 0 so to find the discriminant, D, you use

D = b2 - 4ac

Then if D is greater than 0 the equation has 2 real roots; if D = 0 the equation has one real root and if D is less than 0 the equation has no real roots. So to check this we work out D but we need to know what a, b and c are. From the equation we can see that

a = 1

b = 2

c = 5

so putting these values in to find D:

D = (2)2 - 4(1)(5) = 4 - 20 = -16

so the equation x2 + 2x + 5 = 0 has no real roots.

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Q: Use the discriminant to determine the real roots How many roots are in this problemx2 plus 2x plus 5 equals 0?
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