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If you mean b^2 -4ac then it is the discriminant of a quadratic equation.
If the discriminant equals 0 then the equation has 2 equal roots.
If the discriminant is greater than 0 then the equation has 2 different roots.
If the discriminant is less than 0 then it has no real roots.
What else can I help you with?
A function to compute the real roots of the quadratic equation?
Where the equation is ax2 + bx + c the roots are given by the solutions to : (-b +/- sqrt(b2 - 4ac))/2a
How do you find the discriminant of a equation?
The general form of a quadratic equation is ax2 + bx + c = 0 where a is not zero, a, b and c are constants. The discriminant is b2 - 4ac
What does the rule for a quadratic function tell you about how the graph of the function will look?
If the quadratic function is written as ax2 + bx + c then if a > 0 the function is cup shaped and if a < 0 it is cap shaped. (if a = 0 it is not a quadratic) if b2 > 4ac then the equation crosses the x-axis twice. if b2 = 4ac then the equation touches the x-axis (is a tangent to it). if b2 < 4ac then the equation does not cross the x-axis.
What is the discriminant of a quadratic function?
The form of the quadratic is ax2+bx+c, so the discriminant is b2-4ac.
What are the first four steps in the derivation of the quadratic formula of ax2 plus bx plus c equals 0?
The first step is to show an example of the quadratic equation in question because the formula given is only the general form of a quadratic equation.
What is the formula of a quadratic equation?
The quadratic equation in standard form is: ax2 + bx + c = 0. The solution is x = [-b ± √b2- 4ac)] ÷ 2a You can use either plus or minus - a quadratic equation may have two solutions.
When the roots are equal of a quadratic equation?
Write the quadratic equation in the form ax2 + bx + c = 0 The roots are equal if and only if b2 - 4ac = 0. The expression, b2-4ac is called the [quadratic] discriminant.
What is the equation for finding the discriminant?
The discriminant of the quadratic polynomial ax2 + bx + c is b2 - 4ac.
B2 -4ac in the quadratic equation ax2 plus bx plus c equals 0?
Full equation is (-b +/- sqrt(b2 - 4ac))/2a. Try it with x2 - 2x - 3, where a = 1, b = -2 and c = -3...
What is the quadratic formula?
x = [−b ± √(b2 − 4ac)]/2aA, B, and C can all correspond to the original quadratic equation as follows: ax2 + bx + c = 0The quadratic formula can only be used if the quadratic equation is equal to zero.If [ Ax2 + Bx + C = 0 ], thenx = [ -B +/- sqrt( B2 - 4AC ) ]/ 2A
When is there no real solutions for a quadratic equation?
It's when ax2+bx+c=0 if b2-4ac= is negative
How do you solve a quadratic equation that will not factor?
How you solve an equation that doesn't factor is to plug a quadratic equation's format; ax2+bx+c into the quadratic formula which is x=-b+square root to (b2-4ac)/2a.
What does quadratic formulas look like?
ax2 +bx + c To find roots of any quadratic equation. X = - b (+/-) sqrt(b2 - 4ac)/2a
Equation that can be expressed in the form of the equation y equals ax2 plus bx plus c?
A quadratic equation.
What is the general equation for quadratics?
The general quadratic equation is ax2 + bx + c = 0 The two solutions are: x = [ (negative b) plus or minus the square root of (b2 - 4ac) ] all divided by (2a).
A function to compute the real roots of the quadratic equation?
Where the equation is ax2 + bx + c the roots are given by the solutions to : (-b +/- sqrt(b2 - 4ac))/2a
How do you find the discriminant of a equation?
The general form of a quadratic equation is ax2 + bx + c = 0 where a is not zero, a, b and c are constants. The discriminant is b2 - 4ac
