Let d= number of dimes
q= number of quarters
d=2q
.25q+.10d=4.50
.25q+.10(2q)=4.50
.25q+.20q=4.50
.45q=4.50
q=10
d=2q
d=2(10)
d=20
Therefore, there are 10 quarters totaling $2.50 and 20 dimes totaling $2.00.
7 quarters 2 dimes 4 nickels
12 quarters and 6 dimes 2(.25x) + .10x = 3.60 50x + 10x = 360 60x = 360 x = 6
Chen has 8 nickels, 2 dimes, and 6 quarters.
7 nickels, 4 dimes, 3 quarters
Coin or banknote: Quantity: dollars half-dollars quarters dimes nickel pennies cents dollars half-dollars quarters dimes nickels pennies cents 4 quarters equals: 4 quarters equals 1 dollar
12 quarters 6 dimes
7 quarters 2 dimes 4 nickels
12 quarters and 6 dimes 2(.25x) + .10x = 3.60 50x + 10x = 360 60x = 360 x = 6
Chen has 8 nickels, 2 dimes, and 6 quarters.
70 - 30 = 40, 40/2 - 20, so there are 20 dimes and 50 quarters
It's not possible to give a specific answer without knowing how the numbers of each coin are related. Otherwise there are hundreds of possible combinations; for example278 quarters, 0 dimes, 0 nickels277 quarters, 0 dimes, 5 nickels277 quarters, 1 dime, 3 nickels277 quarters, 2 dimes, 1 nickel276 quarters, 0 dimes, 10 nickelsand so on
Sally has 76 Quarters and 24 Dimes. I hope that I am not doing your homework for you =)
30 quarters equals $7.50 42 dimes equals $4.20 That adds up to 72 coins with a value of $11.70
7 nickels, 4 dimes, 3 quarters
it took a few mins to figure it out but its 36 quarters and 39 dimes
Coin or banknote: Quantity: dollars half-dollars quarters dimes nickel pennies cents dollars half-dollars quarters dimes nickels pennies cents 4 quarters equals: 4 quarters equals 1 dollar
$5.40