0
0.016L
Wiki User
∙ 14y ago
Add your answer:
Earn +20 pts
What is keq for the reaction 2HCI(g) H2(g) plus Cl2(g)?
For 2HCl(g) ==> H2(g) + Cl2(g) the Keq = [H2][Cl2]/[HCl]^2
What is the density of an object with a mass of 500 g and has a volume of 25 cm?
The volume cannot be 25 cm, since that is not a volume measure. Assuming the volume is 25 cm3, Density = mass/volume = 500 g / 25 cm3 = 20 grams per cm3
What volume will the Cl2 occupy at STP?
stupid question
What is the volume of an object if the density is 0.45 g ml and the mass is 25 g?
25/.45=55.555555555555555555555555555555555555555555555555556 ml or 551/2 ml
What is the mass of a sponge that has a density of 0.25 g cm3 and a volume of 60cm3?
25 g/cm3 x 60 cm3 = 1500 g
What is Keq for the reaction H2(g) plus Cl2(g) 2HCl(g)?
For 2HCl(g) ==> H2(g) + Cl2(g) the Keq = [H2][Cl2]/[HCl]^2
What is keq for the reaction 2HCI(g) H2(g) plus Cl2(g)?
For 2HCl(g) ==> H2(g) + Cl2(g) the Keq = [H2][Cl2]/[HCl]^2
What is the density of an object with a mass of 500 g and has a volume of 25 cm?
The volume cannot be 25 cm, since that is not a volume measure. Assuming the volume is 25 cm3, Density = mass/volume = 500 g / 25 cm3 = 20 grams per cm3
What is he necessary amount of chlorine needed to prepare 25.00 g of hydrogen chloride by reacting hydrogen with chlorine?
H2 (g) + Cl2 (g) --> 2 HCl (g) 25.00 g HCl x 1 mol HCl x 1 mol Cl2 x 70.90 g Cl2 = 24.3 g Cl2 are needed. ................... 36.46 g HCl . 2 mol HCl .. 1 mol Cl2
What is keq for the reaction 2hcl gh2 g cl2 g?
Keq=[H2][Cl2]/[hcl]^2
WHAT IS Keq for the reaction 2HCI(g) H2(g) plus CI2(g)?
For 2HCl(g) ==> H2(g) + Cl2(g) the Keq = [H2][Cl2]/[HCl]^2
What is k eq for the reaction 2HCI(g) H2(g) plus CI2(g)?
For the reaction 2HCl(g) ==> H2(g) + Cl2(g), the Keq = [H2(g)][Cl2(g)]/[HCl(g)]^2
There is an equilibrium mixture of B2 C2H2 and HCN Which adjustments to the system will cause more reactants to form?
Br2(g) + 5F2(g) 2BrF5(g)-1.Removing F2 from the system. 2. Increasing the volume of the system.
What reactant is limiting if 3000 cm3 of Cl2 at STP react with a solution containing 25 grams of NaBr?
Cl2 + 2NaBr => Br2 + 2NaCl One mole Cl2 reacts with 2 moles NaBr Cl2 = 71 NaBr = 102.9 Molar volume = 22.414 L/mole for ideal gas @STP 3L Cl2 = 3/22.414 = 0.1338 mole 25g NaBr = 25/102.9 = 0.2430 mole 0.1338 moles Cl2 requires 0.2676 moles NaBr for complete reaction The NaBr is the limiting reagent
A piece of lead has a density of 11.3 g per cm cubed and a mass of 282.5 g. What is its volume?
Volume = mass /densityHere mass = 282.5 gDensity = 11.3 g/cm^3Plugging in the given formula for volume we get Volume = 282.5/11.3 = 25 cm^3
What volume will the Cl2 occupy at STP?
stupid question
Find the density of a rock that has a mass of 25g and a volume of 5cm3?
Density is mass over volume, so divide 25 by 5(25 / 5) = 5 g/cm3 or g/cc
