answersLogoWhite

0

4*5+2*8=176

User Avatar

Wiki User

13y ago

What else can I help you with?

Related Questions

What is the answer to parentheses 43 minus 19 parentheses plus parentheses 16 minus 14 parentheses parentheses 4 parentheses and how did you get the answer?

(43 - 19) + (16 - 14)(4)= 24 + (2)(4)= 24 + 8= 32


Where would the parentheses be in 30-4 times 2 plus 5 equals 2?

30 - 4(2+5) = 2 This makes: 30 - 4(7) = 2 30 - 28 = 2


2 plus parentheses 4 plus 7 parentheses equals?

2+(4+7)= 2+10= 12 so, the answer is twelve the correct way to say that arithmetic problem would be..... two plus the quantity four plus seven


What is the value of 2 parentheses minus 3 minus 5 parentheses minus parentheses 2 plus 2 parentheses?

-20 Yes, that's correct. This is what it means:- 2(-3-5)-(2 + 2) And that is 2 x (-3-5) - (2 +2) = 2 x (-8) -(4) = -16 - 4 = -20


Where do you put the parentheses in 9 plus 4 x 2 - 3?

(9+4)x(2-3)


What is 4 times 4 plus 2?

4 times 4 plus 2 is 18.


Where would you put parentheses around the following equation using the order of operations to make it true 13 plus 7 minus 6 plus 4 times 2 equals 0?

13 + 7 - (6 + 4) * 2 = 0


What is the answer to 2 plus 3 minus 2 times 1 square plus 4 times 16 square minus 4 times 2?

Two plus 3 minus 2 times 1 squared plus 4 times 16 squared minus 4 times 2 is equal to 1,019.


Whats the factor from of 2xy-4x plus 8y-16?

2xy - 4x plus 8y - 16 equals x plus 4 in parentheses multiplied by 2y minus 4 in parentheses. So, the factors are ( x + 4) and ( 2y - 4) .


What is y plus 3 to the third power plus 2 divided by 4?

It depends on where there are parentheses, if there are any. y + 33 + 2/4 = y + 27.5 (y+3)3 + 2/4 = y3 + 9y2 + 27y + 27.5


How do you remove parentheses -7 -5v-u plus 4?

Remove parentheses from the equation -7 -5v-u plus 4 is simple. All you have to do is find the value of the letter V.


(9xcubed-3) - (4xsquared plus 4) plus (5xcubed plus 5xsquared)?

You can expand the first expression in parentheses, then add or subtract like terms.