The efficiency of a ramp is 75 percent If the amount of work input is 240 J what is the amoun t of useful work output?
The formula for percent work efficiency is:
percent efficiency = (work output/work input) x 100
To find the answer to this question, you just need to plug the
given values into the formula. The problem tells you that the work
input is 240 J and the percent efficiency is 75 %, so
75 = (work output/240) x 100
Now, solve for work output:
-first divide by 100
.75 = (work output/240)
-then multiply by 240
180 J = work output (in units of joules because work is measured
in joules)
And there's your answer. Hope this helped!