08/13/2007, 01:33 PM

jaydfox Wrote:I'm not sure I follow why your solution is

The function is continuous, of course:

And for base e, the first derivative is continuous as well:

However, even at the second derivative, we begin to see problems:

For base e, we get a second derivative of 1 from the left, but 2 from the right. Due to the product rule, the second and higher derivatives will get quite complex, preventing a simple solution.

I see. I guess you are right.

Thanks for the correction.