26 is the least integer whose square root is an irrational number between 5 and 7. This is apparent as the square root of the previous integer (25) is a rational number and since the division method for calculating the square root produces a decimal that continues infinitely without repetition.
The square root of 27 is an irrational number
Irrational. The square root of a positive integer is either an integer, or an irrational number.
Irrational. The square root of a positive integer is either an integer (that is, if the integer is a perfect square), or an irrational number.
No. The square root of an integer is either an integer, or an irrational number.
The square root of 61 is an irrational number
Yes. The square root of a positive integer can only be an integer (if your integer is a perfect square), or an irrational number (if it isn't).
For a start, the square root of any integer is either an integer, or an irrational number.
The square root of a positive integer can ONLY be:* Either an integer, * Or an irrational number. (The proof of this is basically the same as the proof, in high school algebra books, that the square root of 2 is irrational.) Since in this case 32 is not the square of an integer, it therefore follows that its square root is an irrational number.
Irrational.
irrational
The square root of 29 is an irrational number.
No. The square root of an integer is always either an integer or an irrational number.