Since the first term is 10 and second is 13 so difference is three
Then the second term is 13 and third term is 18 so difference is five
Then again the third term is 18 and fourth term is 25 so diference if seven
hence the difference increases as 3,5,7 then the difference between fouth term and fifth term must be 9 so, the next term must be 34.
They are: 10 and 16
Double it every time and so the next number will be 80
This sequence is an arithmetic series that makes use of another series. This sequence advances by adding the series 4, 11, 21, 34, and 50 to the initial terms. This secondary series has a difference of 7, 10, 13 and 16 which advance by terms of 3. So the next three numbers in the primary sequence are 190, 281 and 397.
The first thing to notice is that all the numbers in the sequence are square numbers. 25=5x5 36=6x6 49=7x7 64=8x8 81=9x9 So the next three numbers to be squared are 10, 11 and 12. 10x10=100 11x11=121 12x12=144 Thus, the next three numbers in the sequence are 100, 121, 144 The equation for the sequence is (n+4)2
Well, first you should take note of the pattern. Each of those numbers is increasing by 10. 60 +10=70. 70 + 10= 80. So, just continue the pattern to find the next 3 terms. 80 +10= 90, 90+10 = 100, 100+10+110.
37
10, 8, 6, 4, 2, 0, -2, -4
11, -10, 9
100 200 20
18 34 66
Consecutive terms in the sequence are found by dividing by 2 and adding 2. Therefore, after the number 10 comes 10/2 + 2 = 7.
Ignoring the "9" , then this is a Fibonacci sequence. 2,2,4,6,10 The first two terms are 'seed' terms then successive terms equal the sum of the two previous terms. 2 + 2 = 4 2 + 4 = 6 4 + 6 = 10 The next term would be 6 + 10 = 16.