The given sequence is an arithmetic sequence with a common difference of 6. To find the nth term of this sequence, we can use the following formula:
nth term = first term + (n - 1) x common difference
where n is the position of the term we want to find.
In this sequence, the first term is 1 and the common difference is 6. Substituting these values into the formula, we get:
nth term = 1 + (n - 1) x 6
nth term = 1 + 6n - 6
nth term = 6n - 5
Therefore, the nth term of the sequence 1, 7, 13, 19 is given by the formula 6n - 5.
The nth term is 6n+1 and so the next term will be 31
The nth term is: 5-6n
2n+1
[ 25 - 6n ] is.
T(n) = 25 - 6n
3n+7
The nth term is 4n-1 and so the next term will be 19
To find the nth term of this sequence, we first need to identify the pattern. The differences between consecutive terms are 5, 9, 13, 17, and so on. These are increasing by 4 each time. This means that the nth term can be calculated using the formula n^2 + 4n + 1. So, the nth term for the sequence 5, 10, 19, 32, 49 is n^2 + 4n + 1.
It is: nth term = 5-4n and so the next term will be -19
Appears we are adding 6 each time. So the nth term is a_(n-1)+6 where n-1 is a subscript of a.
The nth term is: 3n+1 and so the next number will be 16
As given, the sequence is too short to establish the generating rule. If the second term was 19 and NOT 29, then the nth term is tn = 6*n + 7 or 6(n+1)+1