To find the 102nd term in the number pattern of multiples of 3, you can use the formula for the nth term of an arithmetic sequence: (a_n = a_1 + (n-1)d), where (a_n) is the nth term, (a_1) is the first term, (n) is the term number, and (d) is the common difference. In this case, the first term ((a_1)) is 3 (the first multiple of 3), the common difference ((d)) is also 3 (since each term is increasing by 3), and we want to find the 102nd term ((a_{102})). Plugging these values into the formula, we get (a_{102} = 3 + (102-1) \times 3 = 3 + 101 \times 3 = 3 + 303 = 306). Therefore, the 102nd term in the number pattern of multiples of 3 is 306.
306
To find the term of 102 in the number pattern of multiples of 3 starting with 3, we can use the formula for the nth term of an arithmetic sequence: (a_n = a_1 + (n-1)d), where (a_n) is the nth term, (a_1) is the first term, (n) is the term number, and (d) is the common difference. In this case, the first term is 3, the common difference is 3 (as we are dealing with multiples of 3), and we want to find the term number when the term is 102. Plugging these values into the formula, we get (102 = 3 + (n-1)3). Simplifying this equation, we find that the term number is 34.
All multiples of 102, which is an infinite number.
The multiples of 102 are numbers that can be evenly divided by 102 without leaving a remainder. To find the multiples of 102, you can multiply 102 by any integer. Some of the multiples of 102 include 102, 204, 306, 408, and so on.
Any number of the form 102*k where k is an integer.
34, 68, 102, 136, 170.
All multiples of 5 end in 0 or 5. So, the only number between 102 and 108 which is a multiple of 5 is 105.
102, 204, 306, 408, 510
There is an infinite number of multiples of 34. The set is 34, 68, 102, 136, 170, 204, 238, 272, 306, 340, 374, 408, 442, 476, 510, and so on.
To find the nth term in a sequence, we first need to identify the pattern or formula that describes the sequence. In this case, the sequence appears to be decreasing by 4, then decreasing by 6, and finally decreasing by 10. This suggests a quadratic pattern, where the nth term can be represented as a quadratic function of n. To find the specific nth term for this sequence, we would need more data points or information about the pattern.
The LCM is: 9,384
i think for 102 it is 1, 2 & 3 but m not 100% sure