what term is 102 in the number pattern multiples of 3?

Answer 1

To find the 102nd term in the number pattern of multiples of 3, you can use the formula for the nth term of an arithmetic sequence: (a_n = a_1 + (n-1)d), where (a_n) is the nth term, (a_1) is the first term, (n) is the term number, and (d) is the common difference. In this case, the first term ((a_1)) is 3 (the first multiple of 3), the common difference ((d)) is also 3 (since each term is increasing by 3), and we want to find the 102nd term ((a_{102})). Plugging these values into the formula, we get (a_{102} = 3 + (102-1) \times 3 = 3 + 101 \times 3 = 3 + 303 = 306). Therefore, the 102nd term in the number pattern of multiples of 3 is 306.