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Q: What 13 acres equal how many feet in length and width?
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Related questions

What is the length and width of 80 acres squared?

A square with an area of 80 acres has a length and width of 1,867 feet. The diagonal length of the square is 2,640 feet.


What is the Length and width of 99 square acres?

A square with an area of 99 acres has a length and width of 2,077 feet.


A rectangle has a width equal to 8 feet and length equal to 14 feet a similar rectangle has a length equal to 42 feet what is its width?

The width is 24 feet.


What is 250 feet width 500 feet length into acres?

Answer: 125,000 ft² = 2.86960 acres


What is the length and width of 1.5 acres?

If the shape of the parcel is a square, the length and width is 255.6 feet.


You found a property that is 650 feet width and 50 acres length What is the length in feet?

The length is 3,350.76923 feet.


If twentyseventhsof a acres width is 200 ft what is length?

The length of an area of 1/27th of an acre that is 200 feet wide would be about 6.5 feet. It would equal about 1350 square feet.


What is the width and length of 9.5 acres?

643.28 feet x 643.28 feet for a square-shaped lot of 9.5 acres.


How many feet are in the perimeter of 5 acres?

5 acres = 5*43560 square feet = 217800 sq feet. So the length must be greater than or equal to sqrt(217800) feet ie 466.7 feet. The length can be any number greater than this, with the width = 217800/Length feet. So the perimeter must be greater than or equal to 4*466.7 = 1866.8 feet. There is no upper limit.


What is Length of 5.5 acres 200 feet wide?

5.5 acres, with a width of 200 ft, has a length of: 1189.76 ft. ( 1189' 9" ).


How many acres are there in a plot 50 feet wide by 1320 feet long?

The idea is to multiply length x width. That will give you an answer in square feet. Then you convert that to acres.


How many feet length x width equals .5 acres?

0.5 acres = 21,780 square feet.So you know that (length) times (width) must be 21,780 but there are noother constraints on what the dimensions must be. There are an infinite numberof possible length/width combinations.