No answer exists. Any 2 consecutive numbers will produce an odd sum.
Two consecutive numbers which add up to 91 are the numbers one half either-side of 91/2 = 45.5. Therefore, the numbers are 45 + 46 = 91.
two consecutive 4- digit numbers have a sum of 9173.what are the numbers?
The numbers are 54 and 56.
No, the sum of two consecutive numbers is always an odd number, and is not divisible by two.
The sum of consecutive numbers (starting with 1), is the square of the number of terms you sum, in this case 1600. 1600^2 = 2,560,000
The three consecutive whole numbers you are looking for are 1, 2, and 3. The sum of the first two numbers, 1 + 2 = 3.
Divide the sum of the two consecutive even integers by 2: 90/2 = 45. The smaller of these integers will be one less than 45 and the larger will be one more than 45, so the two consecutive even integers will be 44 and 46.
There is no possible answer. The sum of two consecutive even numbers MUST leave a remainder of 2 when divided by 4. That is, the sum must be divisible by 2 but must not be divisible by 4.
The numbers are 4,586 and 4,587.
The numbers are 55, and 57. Two consecutive integers have an odd sum.
The numbers are -2, -1, 0, 1 and 2.
The numbers are 6 and 8.
The sum of the first 8000000 consecutive numbers is Sn = n(a1 + an)/2 => 8000000(1+800000)/2 Sn = 32000004000000
17 is the only prime number that is the sum of four consecutive prime numbers. 2 + 3 + 5 + 7 = 17
There are none.
The numbers are -53 and -52.
417 and 418
The sum of the first n cubed numbers is: [n*(n+1)/2]2 which is the same as the square of the sum of the first n numbers.
The numbers are -1, 0, 1, 2 and 3.
The sum of three consecutive odd numbers must be divisible by 3. As 59 is not wholly divisible by 3 the question is invalid. PROOF : Let the numbers be n - 2, n and n + 2. Then the sum is 3n which is divisible by 3. If the question refers to three consecutive numbers then a similar proof shows that the sum of these three numbers is also divisible by 3. Again, the question would be invalid.