112 and 113
Two consecutive integers will be 0.5 more and 0.5 less than the quotient of their sum divided by 2. The given sum of the two consecutive integers divided by 2 is -3471.5, so the two consecutive integers are -3472 and -3471.
Find 2 consecutive ODD integers whose sum is -88 ANSWER: -45, -43
Let's denote the smallest odd integer as x. The next three consecutive odd integers would then be x+2, x+4, and x+6. The sum of these four integers is x + (x+2) + (x+4) + (x+6) = 4x + 12. Given that the sum is 112, we have 4x + 12 = 112. Solving for x, we get x = 25. Therefore, the greatest of the four integers is x + 6 = 25 + 6 = 31.
There is a set of two consecutive integers that have a sum of 123; one odd and one even. They are 61 and 62.
112 and 113
Two consecutive integers will be 0.5 more and 0.5 less than the quotient of their sum divided by 2. The given sum of the two consecutive integers divided by 2 is -3471.5, so the two consecutive integers are -3472 and -3471.
Find 2 consecutive ODD integers whose sum is -88 ANSWER: -45, -43
It need not be. 2 and 3 are consecutive integers and their sum is 5, not 31.
The two consecutive integers that have a sum of -105 are -53 and -52.
Two consecutive even integers will be one more and one less than the quotient of their sum divided by 2. The given sum of the two consecutive integers divided by 2 is 25, so the two consecutive integers are 24 and 26.
There is a set of four consecutive even integers whose sum is four. The set is: -2, 0, 2 and 4.
Let's denote the smallest odd integer as x. The next three consecutive odd integers would then be x+2, x+4, and x+6. The sum of these four integers is x + (x+2) + (x+4) + (x+6) = 4x + 12. Given that the sum is 112, we have 4x + 12 = 112. Solving for x, we get x = 25. Therefore, the greatest of the four integers is x + 6 = 25 + 6 = 31.
The smallest is -1
They are 2n+2
107
-52,-53