The numbers are 55, and 57.
Two consecutive integers have an odd sum.
Chat with our AI personalities
112 and 113
Two consecutive integers will be 0.5 more and 0.5 less than the quotient of their sum divided by 2. The given sum of the two consecutive integers divided by 2 is -3471.5, so the two consecutive integers are -3472 and -3471.
Let's denote the smallest odd integer as x. The next three consecutive odd integers would then be x+2, x+4, and x+6. The sum of these four integers is x + (x+2) + (x+4) + (x+6) = 4x + 12. Given that the sum is 112, we have 4x + 12 = 112. Solving for x, we get x = 25. Therefore, the greatest of the four integers is x + 6 = 25 + 6 = 31.
There is a set of two consecutive integers that have a sum of 123; one odd and one even. They are 61 and 62.
Let's represent the three consecutive integers as x, x+1, and x+2. To find their sum, we add these integers together: x + (x+1) + (x+2) = 88. Simplifying the equation gives us 3x + 3 = 88. Subtracting 3 from both sides and then dividing by 3, we find that x = 28. Therefore, the three consecutive integers are 28, 29, and 30, and their sum is indeed 88.