384 is a composite number. All even numbers (except for 2) are composite because they are automatically divisible by 2.
Yes. 384 / 2 = 192
Product = LCM x GCF = 384, sum = 40. Factors of 384 = 2 x 192, 3 x 128, 4 x 96, 6 x 64, 8 x 48, 12 x 34, 16 x 24 That'll do! The numbers are 16 and 24
NO!!!! 384 is an even number, so it is not a prime, because it is divisble by '2' 945 is not prime because it can be divided by '5'.
1 x 384, 2 x 192, 3 x 128, 4 x 96, 6 x 64, 8 x 48, 12 x 32, 16 x 24. 192 + 192
93*2*2=384
As a product of its prime factors in exponents: 27*3 = 384
384
384 divided by 4 is 96 so the 4 odd numbers will be two above and two below. Two below: 93 and 95 Two above: 97 and 99. 93+95+97+99=384
13 + 4^2 = 29 29 + 5^2 = 54 54 + 6^2 = 90 90 + 7^2 = 139 139 + 8^2 = 203 203 + 9^2 = 284 284 + 10^2 = 384 384 + 11^2 = 505 so the next three numbers in the sequence are 284, 384 and 505.
The answer is 3,840. You multiply the numbers in the sequence by 2, 4, 6, 8, then 10. 1 x 2 = 2 2 x 4 = 8 8 x 6= 48 48 x 8 = 384 384 x 10 = 3,840
192
2,3,4,and6
The prime factors of 64 are 2, 2, 2, 2, 2, and 2, or 26. The prime factors of 120 are 2, 2, 2, 3 and 5, or 23, 31 and 51. The least common multiple of two numbers is the product of the largest power of each prime encountered in both numbers. In the case of 64 and 120, these are 26, 31, and 51, so the LCM of 64 and 120 is 960.
336 and 48
192 x 2 = 384
These numbers: 1, 2, 3, 4, 6, 8, 12, 16, 24, 32, 48, 64, 96, 128, 192, 384 in the following combinations equal 384: 1 x 384, 2 x 192, 3 x 128, 4 x 96, 6 x 64, 8 x 48, 12 x 32, 16 x 24, 24 x 16, 32 x 12, 48 x 8, 64 x 6, 96 x 4, 128 x 3, 192 x 2, 384 x 1