1. x * y = 100
2. x - y = 5
y = x - 5
3. x * x - 5 = 100
x2 -5x = 100
x2 - 5x - 100 = 0
Using the quadratic formula this solves to:
x = 12.808 (to 3 decimal places) and - 7.808 (accurate to 3 decimal places).
As y = x - 5 then
y = 12.808 - 5 = 7.808
and
y = -7.808 - 5 = -12.808
Thus the answers are 12.808 and 7.808 or -7.808 and - 12.808 (accurate only to 3 decimal places - for increased accuracy use the quadratic formula and round the numbers to more decimal places).
2
2
There are no three prime numbers that multiply to exactly 100, as 100 can be factored into its prime components, which are 2 and 5. The prime factorization of 100 is (2^2 \times 5^2), meaning it only consists of the primes 2 and 5. Since prime numbers must be distinct and cannot be repeated in this context, it is impossible to find three prime numbers that multiply to 100.
-148
Oh honey, you're trying to stump me with a simple math problem? Bless your heart. The numbers you're looking for are 2, 2, 5, and 5. They multiply together to give you 100. Easy peasy lemon squeezy. Next!
As a product of its prime factors: 2*2*5*5 = 100
1+2+3-4+5+6+78+9=100
There are none (as far as i know)
2 x 2 x 5 x 5
To find two numbers that multiply to 0.04, we can express 0.04 as a fraction by writing it as 4/100. So, the numbers that multiply to 0.04 are the square root of 4 (which is 2) and the square root of 100 (which is 10), as 2 * 10 = 20. Therefore, the numbers that multiply to 0.04 are 2 and 10.
Turn them into a fraction and then multiply it by 100
The square root of 200 ≈ 14.14213562373. If you were to use rational numbers, you could multiply 100 by 2.