10 and 4
10x4 =40
10-4 +6
Homework question: The first numbetr is 4. A rule is multiply by 2 and then subtract 3. What are the first 6 numbers in the pattern
To find three numbers that multiply together to equal 40, we need to consider the prime factors of 40, which are 2, 2, 2, and 5. We can group these prime factors into three numbers: 2, 2, and 10. Therefore, the three numbers that multiply to 40 are 2, 2, and 10.
There are no two real numbers that do. Using complex numbers, these two do: (-3/2 + i√151/2) & (-3/2 - i√151/2) Two numbers that add to -3 and multiply to -40 are -8 & 5 Two numbers that add to 3 and multiply to -40 are 8 & -5 Two complex numbers that add to 3 and multiply to 40 are (3/2 + i√151/2) & (3/2 - i√151/2)
2 2 40
multiply 3 subtract 2
40 = 2 x 2 x 2 x 5
The numbers are 96 and 40
131072 and 2 if you multiply them. 262142 and 2 if you add them. 262146 and 2 if you subtract them. 524288 and 2 if you divide them.
991 and 2 if you multiply them. 1980 and 2 if you add them. 1984 and 2 if you subtract them. 3964 and 2 if you divide them.
22 and 18
18
-42