37+38+39=114
113, 114, 115
114, 115 & 116
114/3 = 38, so the three integers are 37, 38 and 39.
114
Since the average of the three integers will be 114/3 = 38, and the three numbers are consecutive, the numbers will be 36, 38 and 40. Another way to do this problem using algebra is to let the first integer be n, then the next two are n+2 and n+4. Their sum is 3n+6 and it equals 114 So 3n+6=114 and 3n=108 so n=36 then next two numbers must be 38 and 40 since they are consecutive even integers.
2 and 3 are consecutive prime numbers.
No whole 3 consecutive numbers total 46.
2 and 3 are consecutive numbers and they are both prime.
The numbers 2 and 3 are consecutive prime numbers. Are there other pairs of prime numbers which are consecutive numbers?
The only consecutive prime numbers are 2 and 3.
2 and 3 are the only consecutive prime numbers.
2 and 3 are the only example of consecutive prime numbers.