Study guides

☆☆

Q: What 4x y14 and 2x y8 solve using substitution?

Write your answer...

Submit

Still have questions?

Related questions

y=2x+9 and y=x+6

3(5x-2y)=18 5/2x-y=-1

2x-y=3 2/3x-y=-1

To solve the following equation by substitution, we need to have the equal sign. This will help us group the knowns and the unknowns.

Solve this system of equation using substitution 2x plus 6y equals 24 and 3x-2x equals 24 ?Improved Answer:2x+6y = 243x-2x = 24 => x =24Substitute the value of x into the top equation to find the value of y:48+6y = 246y = 24-486y = -24y = -4So: x = 24 and y = -4

When using substitution the answer to y0.5x plus 2 -y-2x plus 4 is y = -2 (x-1.

Use the substitution method to solve the system of equations. Enter your answer as an ordered pair.y = 2x + 5 x = 1

what is the solution of x-5y=10 and 2x-10y=20

If: x+y = 4 and y = 2x+1 Then: 4-x = 2x+1 => 3 = 3x => 1 = x So by substitution: x = 1 and y = 3

-34

2x+7y=29 x=37-8y

y = 4x - 8 y = 2x + 10 The substitution means to: Find the intersection point of their graphs, which is the common solution of this linear system of equations: 4x - 8 = 2x + 10 2x = 18 x = 9 y = 4(9) - 8 = 36 - 8 = 28 or y = 2(9) + 10 = 28 Thus the solution is (9, 28)

To solve a system of equations using substitution you solve one of the equations for one of the variables then substitute that into the other equation to solve for the other variable. For example. y = 6x 2x + 3y = -20 The first equation has already been solved for y. So, you simply substitute that into the second equation. 2x + 3(6x) = -20 2x + 18x = -20 20x = -20 x = -20/20 = -1 Now you have solved for x. You can substitute your answer for x back into the first equation to solve for y. y = 6x = 6(-1) = -6 Putting it all together... x = -1 y = -6

-2x+5 x=-3 --original equation-2(-3)+5 --use substitution property6+5 --solve.11 --final answer is 11.

Mathematical substitution is the process of using one equation to solve for multiple variables. For example: Equation 1: x + y = 4 Equation 2: 2x + y = 16 Using equation 1, solve for y: y = 4 - x <-- Plug this into equation 2. This is substitution because you are replacing y in equation 2 with what y is equal to in equation 1. 2x + y = 16 ----> 2x + (4 - x) = 16 Now you can solve for x: x + 4 = 16; x = 12 You can then substitute the value of x back into the equation that is solved for y: y = 4 - 12; y = -8 Check both equations: Equation 1: -8 + 12 = 4; 4 = 4 (Correct) Equation 2: 2(12) + (-8) = 16; 24 - 8 = 16; 16 = 16 (Correct) We have successfully used substitution to solve for two different variables, x and y.

I would use substitution. Turn the second equation into y=8-2x, put it into the first and solve for x. Then put x into one of the equations and solve for y.So...2x-3(8-2x)=24 --> 2x-24+6x=24 --> 8x=48 --> x=6y=8-(2x6) --> y=8-12 --> y=-4

If you mean: 2x-y=5 and x-2y=1 then by multiplication, elimination and substitution it works out that x=3 and y=1

2x + 5 - 5 = 2x. You can not solve for x because this is not an equation.

2x-y = 4 and 2y = 4x-6 pick either equation and solve for one of the variables the first equation: y = -4 + 2x plug in the value of variable you solved for into the other equation 2(-4 + 2x) = 4x -6 then solve -8 + 2x = 4x-6 -2 = 2x x= -1 then plug in the value you have found into either original equation to find the value of the other variable 2(-1) - y = 4 -2 - y = 4 -y = 6 y = -6

x = -2 and y = 1

Solve for y: f(-5)=13+2x

Algebraic equations with two variables will need two equations to be able to solve it. Then, you can solve it with either substitution, adding/subtracting them together, or graphing! Those are the basic steps... For example: An instance of substitution: 2x + 1 = y + 2 x + y = 3 You could isolate y in the second equation to equal y = 3-x. Then in the first equation, substitute y with what it equals to 2x + 1 = 3-x+2 Then you can solve for x!

(2,3)

2x+a=p 2x=p-a x=.5p-.5a

Isolate one of the variable using inverse operations. Then solve. Example: 2x + 4y = 0 --subtract 4y>> 2x = -4y --divide by -4>> -1/2x = y --plug in your variable -->>