If: x+y = 4 and y = 2x+1
Then: 4-x = 2x+1 => 3 = 3x => 1 = x
So by substitution: x = 1 and y = 3
2x-3y=13
-2
how do you use the substitution method for this problem 2x-3y=-2 4x+y=24
2x + 2y = 44x + y = 1There are many methods you can use to solve this system of equations (graphing, elimination, substitution, matrices)...but no matter what method you use, you should get x = -1/3 and y = 7/3.
This is not Calculus.y=7(Already solved)substiute y=7 into y=8xtherefore 7 = 8xtherefore x = 7/8
(2,3)
2x-3y=13
-2
how do you use the substitution method for this problem 2x-3y=-2 4x+y=24
2x + 2y = 44x + y = 1There are many methods you can use to solve this system of equations (graphing, elimination, substitution, matrices)...but no matter what method you use, you should get x = -1/3 and y = 7/3.
This is not Calculus.y=7(Already solved)substiute y=7 into y=8xtherefore 7 = 8xtherefore x = 7/8
x+2(x+3) = 12 x+2x+6 = 12 x+2x = 12-6 3x = 6 x = 2 and y = 5
y=16 x= -4
16
Since the second equation is already solved for "y", you can replace "y" by "9" in the other equation. Then solve the new equation for "x".
You'd need another equation to sub in
the answer