a+a*r+a*r^2+...+a*r^n a = first number r = ratio n = "number of terms"-1
n= total number and r= total number chosen
The number of R-combinations in a set of N objects is C= N!/R!(N-R)! or the factorial of N divided by the factorial of R and the Factorial of N minus R. For example, the number of 3 combinations from a set of 4 objects is 4!/3!(4-3)! = 24/6x1= 4.
Give the numbers some names: End result number ==> R Base number ==> B You said that 2.75 percent of B reached R. .0275 B = R Divide both sides of this equation by .0275 B = R / .0275 Divide the 'end result' by 0.0275. The answer will be the 'base number'.
By the letter R.
armoramberbikerboxercatercolorcoverdinerdiverelderfavorflourgiverhikerhumorinnerjokerlaborlemurlaserloserliterleverloverlivermajormakermayormanormotorminormoverneverownerolderpokerpowerrazorriverrumorsaversavorseversobertatertowertakertruertumorwaterwiper
Stall.
quadsquits
* jumbo * giant * hefty * large
congo
One option is the word conga.
empty
. This is same as half of r.
r/2-8
a+a*r+a*r^2+...+a*r^n a = first number r = ratio n = "number of terms"-1
n= total number and r= total number chosen
Combination Formula ProofGENERIC:Let C(n,r) be the number of ways to generate unordered combinationsThe number of ordered combinations (i.e. r-permutations) is P(n,r)The number of ways to order a single one of those r-permutations P(r,r)The total number of unordered combinations is the total number of ordered combinations (i.e. r-permutations) divided by the number of ways to order each combinationThus, C(n,r) = P(n,r)/P(r,r) = [n!/(n-r)!]/r!/(r-r)!] = n!/r!(n(n-r)!SPECIFIC:Let C(52,5) be the number of ways to generate unordered poker handsThe number of ordered poker hands is P(52,5) = 311,875,200The number of ways to order a single poker hand is P(5,5) = 5! = 120The total number of unordered poker hands is the total number of ordered hands divided by the number of ways to order each handThus, C(52,5) = P(52,5)/P(5,5)