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Q: What are the two consecutive whole numbers of 80?

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There are two consecutive odd integers. The numbers are 39 and 41.

6399 and 6401

73

8 and 9 because square root of 64=8 and square root of 81=9

Whole numbers means no decimal places have to be represented and no fractions can be associated with it. so 80 is a whole number and the whole number before it is 79 and the whole number after it is 81

This answer cannot be answered because two consecutive numbers consist of one odd number and one even number, and the sum of an odd number plus an even number is always an odd number.

There aren't two whole numbers that satisfy those conditions. If that was -80, you could use 8 and -10.

73

Nine of them.

65

73

73

78+79+80=237

An infinity. There is an infinity of numbers between any two numbers. I you want whole numbers, there are 31.

The numbers from 75 to 84 are rounded off to 80 to the nearest ten

No two whole numbers satisfy these parameters. However, -11.787088*6.787088=-80 (within 10-5) and -11.787088+6.787088=-5

Two numbers have a product of 80 their sum is 24?

It is 23 because 17+19+21+23 = 80

73

17, 19, 21 and 23.

Twenty of them including 80 and 100

Your question was cut off, but you probably meant to say between 77 and 80. If that is what you meant, then the answer would be 78 and 79.

There are no "two consecutive integers" that can do that.But there are two consecutive even integers that can: 8 and 10 .

The common denominator of any two or more whole numbers, such as 60 and 80, will always be one (1) because common denominators refers to the denominators of two or more fractions or mixed numbers, not whole numbers. So, a set of whole numbers (x,x) would have to be converted to their fraction equivalents, i.e., x/1, which will always yield a denominator of 1.

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