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Yes. The slope, or rate, is constant. The rate being represented is speed. If the slope is a negative constant, the object is losing distance (going towards) from the orgin at at a constant speed.
the slope would be speed.
A straight slanted slope on a velocity-time graph indicates that the object is moving with a constant acceleration.
If you are plotting distance versus time it is a straight line with slope 300000
Yes. Speed is the rate at which distance changes over time. In calculus terms v = dx/dt, or the slope of the distance vs. time graph. If the slope of the distance vs. time graph is a straight line, the speed is constant.
a straight line with a positive slope
The answer is TRUE because it is a straight line as the graph shows below. http://www.batesville.k12.in.us/physics/apphynet/Measurement/Images/d_vs_t2_graph.gif
The answer is TRUE because it is a straight line as the graph shows below. http://www.batesville.k12.in.us/physics/apphynet/Measurement/Images/d_vs_t2_graph.gif
Straight line
Yes. The slope, or rate, is constant. The rate being represented is speed. If the slope is a negative constant, the object is losing distance (going towards) from the orgin at at a constant speed.
it is a positive relationship
Straight line
A straight horizontal one does.
the slope would be speed.
A straight slanted slope on a velocity-time graph indicates that the object is moving with a constant acceleration.
No. It means that the object is going at a constant speed.
If you are plotting distance versus time it is a straight line with slope 300000