Just multiply all the natural numbers from 1 to the number. For example, 7! = 7 x 6 x 5 x 4 x 3 x 2 x 1 = 5040.
The time complexity of an algorithm with a factorial time complexity of O(n!) is O(n!).
The most efficient way to implement a factorial algorithm in a programming language is to use an iterative approach rather than a recursive one. This involves using a loop to multiply the numbers from 1 to the given input number to calculate the factorial. This method is more memory-efficient and faster than using recursion.
P(n,r)=(n!)/(r!(n-r)!)This would give you the number of possible permutations.n factorial over r factorial times n minus r factorial
factorial using recursion style in c++ is unsigned int fact(unsigned int a) { if (a<=1) return 1; else { f*=fact(a-1); return a; } } when using looping structure factorial is unsigned int fact (unsigned int n) { unsigned int i,f=1; for(i=1;i<=n;i++) f*=i ; return f; }
Pseudo code+factorial
write an algorithm to print the factorial of a given number and then draw the flowchart. This looks like someones homework, defiantly someone looking for the easy way. When it comes to programming, the more you do the better you get. Experience counts (making your own mistakes and learning from the mistake).
Kat
Write an algorithm to find the root of quadratic equation
this is a code for calculating it recursivelly: float Factorial (float n) { if (n<=1) return 1.0; else return n* Factorial(n-1); }
If you have N things and want to find the number of combinations of R things at a time then the formula is [(Factorial N)] / [(Factorial R) x (Factorial {N-R})]
Factorial (n) = n * Factorial (n-1) for all positive values n given Factorial (1) = Factorial (0) = 1. Pseudo-code: Function: factorial, f Argument: positive number, n IF n<=1 THEN RETURN 1 ELSE RETURN n * f(n-1) END IF
factorial