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What are all the multiples of 100?
There are an infinite number of multiples of 100. 100, 200, 300,400, ....
What is the multiple of 100?
There are several multiples of 100. The multiples of 1 are: 1, 2, 3, 4, 5, 6, 7, 8 ect. All you have to do is add 2 zeroes. The multiples of 100 are: 100, 200, 300, 400, 500, 600, 700, 800 ect.
What are multiples of 100?
The Multiples of 100 is 100,200,300,400,500,600,700,800,900 and so on. If your doing multiples from 1 to 100 then the only multiple of 100 is 100. Multiples Definition = A number Multiples by a number to = A number For example - I need to know the multiples of 7 7 X 1 = 7 7 X 2 = 14 ... and so on The products of the numbers are called multiples.
Multiples of 2 all the way up to 100?
2,4,6,8,10,12,14,16,18,20,22,24,26,28,30,32,34,36,38,40,42,44,46,48,50,52,54,56,58,60,62,64,66,68,70,72,74,76,78,80,82,84,86,88,90,92,94,96,98,100
How many one digit factors are in each whole number 1 to 100?
' 1 ' is a factor of every whole number . . . . . 100 of them' 2 ' is a factor of every even number . . . . . 50 of them' 3 ' has 33 multiples up to 100 . . . . . 33 of them' 4 ' has 25 multiples up to 100 . . . . . 25 of them' 5 ' has 20 multiples up to 100 . . . . . 20 of them' 6 ' has 16 multiples up to 100 . . . . . 16 of them' 7 ' has 14 multiples up to 100 . . . . . 14 of them' 8 ' has 12 multiples up to 100 . . . . . 12 of them' 9 ' has 11 multiples up to 100 . . . . . 11 of themTotal . . . . . . . . . . . . . . . . . . . . . . . . . 281 one-digit factors in all whole numbers 1 to 100 .
How do you write a C program using an integer array to print array numbers up to 100 and then remove all numbers that are divisible by 2 and print out the remaining numbers and continue for 3 to 9?
#include<stdio.h> #include<conio.h> void main() { int i, a[100]; clrscr(); printf("Numbers from 1 to 100"); for(i=1;i<=100;i++) printf(" %d",a[i]); printf("Numbers from 1 to 100 without multiples of 2"); for(i=1;i<=100;i++) { if (a[i]%2 !=0) printf(" %d",a[i]); } printf("Numbers from 1 to 100 without multiples of 3"); for(i=1;i<=100;i++) { if (a[i]%3 !=0) printf(" %d",a[i]); } printf("Numbers from 1 to 100 without multiples of 4"); for(i=1;i<=100;i++) { if (a[i]%4 !=0) printf(" %d",a[i]); } printf("Numbers from 1 to 100 without multiples of 5"); for(i=1;i<=100;i++) { if (a[i]%5 !=0) printf(" %d",a[i]); } printf("Numbers from 1 to 100 without multiples of 6"); for(i=1;i<=100;i++) { if (a[i]%6 !=0) printf(" %d",a[i]); } printf("Numbers from 1 to 100 without multiples of 7"); for(i=1;i<=100;i++) { if (a[i]%7 !=0) printf(" %d",a[i]); } printf("Numbers from 1 to 100 without multiples of 8"); for(i=1;i<=100;i++) { if (a[i]%8 !=0) printf(" %d",a[i]); } printf("Numbers from 1 to 100 without multiples of 9"); for(i=1;i<=100;i++) { if (a[i]%9 !=0) printf(" %d",a[i]); } getch(); }
How many multiples of 2 in 100?
10 is two in multiples of 2 to 100
Multiples of 2 from 1 to 100?
Alright, buckle up buttercup. Multiples of 2 from 1 to 100 are 2, 4, 6, 8, 10, and so on up to 100. It's like counting by twos, but without all the unnecessary numbers in between. So, grab a calculator if you need to, or just use that brain of yours to figure it out.
How do you use a sieve of Eratosthenes?
1.draw up a chart 1-100 2.get rid of 2's multiples 3.get rid of 3's multiples 4.get rid of 5's multiples 5.get rid of 7's multiples 6. all the left over numbers are prime.
100 multiples of 2?
the multiples of 2 are 2,4,6,8,10,12,14,16,18,20,22,24,26,28,30,32,34,36,38,40,42,44,46,48,50,52,54,56,58,60,62,64,66,68,70,72,74,76,78,80,82,84,86,88,90,92,94,96,98,100
What are all of the multiples of 20?
All the multiples of 20 cannot be listed since they are infinite in number. They start 20, 40, 60, 80, 100, ...
How many numbers from 1 to 100 are multiples of 2 3 4 6 8 9?
Assuming you mean that you want the number of multiples of each, then for 1-100: number of multiples of 2 = 50 number of multiples of 3 = 33 number of multiples of 4 = 25 number of multiples of 6 = 16 number of multiples of 8 = 12 number of multiples of 9 = 11 Assuming you mean that you want the numbers that are multiples of 2, 3, 4, 6, 8 or 9, then some numbers may be multiples of more than one (for example 12 is a multiple of 2, 3, 4 and 6) and so a straight addition of the number of multiples of each cannot be done: Consider 2, 4 and 8 Every multiple of 4 or 8 is also a multiple of 2, so all the multiples of 4 and 8 are counted by the multiples of 2. Consider 3 and 9 Every multiple of 9 is also a multiple of 3, so all the multiples of 9 are counted by the multiple of 3 Consider 2, 3 and 6. Every multiple of 6 is an even multiple of 3, so are counted in both the multiples of 2 and 3. So the total number of multiples of 2, 3, 4, 6, 8 or 9 is the number of multiples of 2 plus the number of multiples of 3 minus the number of multiples of 6: For 1 to 100, Number of multiples of 2 = 50 Number of multiples of 3 = 33 Number of multiples of 6 = 16 So number of multiples of 2, 3, 4, 6, 8 or 9 in 1-100 is 50+33-16 = 67. Assuming you mean that they are multiples of all of 2, 3, 4, 6, 8 and 9, then they must be multiples of the lowest common multiple of 2, 3, 4, 6 ,8, 9 2 = 21, 3 = 31, 4 = 22, 6 = 2131, 8 = 23, 9 = 32 LCM = highest power of the primes used = 2332 = 72 Thus all numbers that are multiples of 2, 3, 4, 6, 8 and 9 are multiples of 72, which means between 1 and 100 only 1 number is a multiple of all of them, namely 72
