The question has provided the answer - it is 180°.
If the question is asking, "What is the name given to angles that add up to 180°?"
then the answer is supplementary angles.
Supplementary angles ad up to 180 degrees. If one angle is 96, how much more do you need to get to 180? 180 - 96= 84 degrees
To prove that the base angles of an isosceles trapezoid are congruent, consider an isosceles trapezoid ( ABCD ) with ( AB \parallel CD ) and ( AD \cong BC ). By the properties of parallel lines, the angles ( \angle DAB ) and ( \angle ABC ) are consecutive interior angles formed by the transversal ( AD ) and ( BC ), respectively, thus ( \angle DAB + \angle ABC = 180^\circ ). Similarly, the angles ( \angle ADC ) and ( \angle BCD ) also sum to ( 180^\circ ). Since ( AD \cong BC ) and the trapezoid is isosceles, the two pairs of opposite angles must be equal, leading to ( \angle DAB \cong \angle ABC ) and ( \angle ADC \cong \angle BCD ), proving that the base angles ( \angle DAB ) and ( \angle ABC ) are congruent.
There cannot be a proof since the statement need not be true.
no because all of the angles in a triangle need to ad up to 180 degrees. a right angle is of course 90 degrees and an obtuse angle is any number higher than 90 degrees. therefor you cannot have a 90 degree angle and have another angle with a degree higher than that because 90+90=180 degrees.
Given: AD perpendicular to BC; angle BAD congruent to CAD Prove: ABC is isosceles Plan: Principle a.s.a Proof: 1. angle BAD congruent to angle CAD (given) 2. Since AD is perpendicular to BC, then the angle BDA is congruent to the angle CDA (all right angles are congruent). 3. AD is congruent to AD (reflexive property) 4. triangle BAD congruent to triangle CAD (principle a.s.a) 5. AB is congruent to AC (corresponding parts of congruent triangles are congruent) 6. triangle ABC is isosceles (it has two congruent sides)
The symbol for an angle bisector is typically represented by a ray or line segment that divides an angle into two equal parts. In geometric notation, it may be denoted as ( \overline{AD} ) if ( D ) is the point on the angle's interior where the bisector intersects. Additionally, the angle bisector is often associated with the notation ( \angle ABC ) where ( D ) lies on the ray ( \overline{AC} ), indicating that ( \overline{AD} ) bisects ( \angle ABC ).
The Roman emperor Marcus Aurelius ruled from AD 161-180.
Let D represent the point on BC where the bisector of A intersects BC. Because AD bisects angle A, angle BAD is congruent to CAD. Because AD is perpendicular to BC, angle ADB is congruent to ADC (both are right angles). The line segment is congruent to itself. By angle-side-angle (ASA), we know that triangle ADB is congruent to triangle ADC. Therefore line segment AB is congruent to AC, so triangle ABC is isosceles.
Both base angles of an Isosceles triangle are by definition the same and, as the internal angles of a triangle must ad up to 180 degrees (again by definition), the the 3rd angle must = 180 - 2 times Y,
If you have an equilateral triangle ABC, then draw the line from A to D, the mid point of BC. Then in trangles ABD and ACD, AB = AC (equilateral), BD = DC (D is midpoint), and AD is common so these two triangles are congruent and so angle ABD = angle ACD. That is, angle ABC = angle ACB. Similarly the third angle can be shown to be the same. Thus an equilateral triangle is also equiangular. Now, sum of the interior angles of any triangle is 180 degrees. So since sum of three equal angles measures is 180 degrees, they must be 60 degrees each, i.e. NOT 90 degrees so there is no right angle..
18
0(zero) Angle of incidence = angle of reflection