Q: What are 2 consecutive integers that equal 56?

Write your answer...

Submit

Still have questions?

Continue Learning about Math & Arithmetic

x + (x + 2) + (x+ 4) = 162 ----> 3x + 6 = 162 ----> x = 52 ----> The integers are 52, 54, and 56.

The equation for this problem would be x + (x + 2) = 56.After combining the two x's, we get 2x + 2 = 56, then 2x = 54, which brings us to find that x = 27. So, 27 is the first odd integer. Since it is two consecutive odd integers, we need to add 2 to 27, giving us 29. Thus, the two consecutive odd integers whose sum is 56 are 27 and 29.

58

Actually the problem does not have a solution with the constraint that the two numbers are consecutive integers. With consecutive integers, one of the integers will be odd and the other one even. An even plus an odd always equals an odd, and you want them to add up to 56, which is an even number. 27.5 + 28.5= 56. steps shown below: x+ (x+1)=56 2x+1 = 56 2x= 56-1 2x= 55 x=55/2 x=27.5 second number is x +1= 27.5+1= 28.5

The numbers are 0, 2, 4, 6, 8 and 10.

Related questions

There are two consecutive even integers that equal -298: -150 and -148.

-7 multiplied by -8 = 56

I think you mean consecutive even integers: 20 & 22

x + (x + 2) + (x+ 4) = 162 ----> 3x + 6 = 162 ----> x = 52 ----> The integers are 52, 54, and 56.

-4, -2, 0, and 2 are the four consecutive even integers. When you add them up they equal -4.

what is the formula to use to solve the product of two consecutive odd integers

There are two consecutive even integers: 90 and 92.

The equation for this problem would be x + (x + 2) = 56.After combining the two x's, we get 2x + 2 = 56, then 2x = 54, which brings us to find that x = 27. So, 27 is the first odd integer. Since it is two consecutive odd integers, we need to add 2 to 27, giving us 29. Thus, the two consecutive odd integers whose sum is 56 are 27 and 29.

58

Actually the problem does not have a solution with the constraint that the two numbers are consecutive integers. With consecutive integers, one of the integers will be odd and the other one even. An even plus an odd always equals an odd, and you want them to add up to 56, which is an even number. 27.5 + 28.5= 56. steps shown below: x+ (x+1)=56 2x+1 = 56 2x= 56-1 2x= 55 x=55/2 x=27.5 second number is x +1= 27.5+1= 28.5

The numbers are 0, 2, 4, 6, 8 and 10.

Not possible in consecutive integers, nearest is consecutive even integers: 148 & 152