Itself and itself doubled which are 235 and 470
They are: 1, 5, 47 and 235
1 and 235 5 and 47 are factor pairs of 235 235 and 470 have a common factor of 235
235 and 470
They are members of the infinite set of numbers of the form 235*k where k is an integer. Since the set is infinite, it is not possible to list them.
If that's 235, 235 does. If that's 2, 3 and 5, 30 does.
235 532
234 and 1.
The positive integer factors of 235 are: 1, 5, 47, 235
Numbers that have only 2 factors are prime numbers
The factors of 235 are 1, 5, 47, 235. For them to be common, they need to be compared to another set of factors.
Let the odd numbers be n-4, n- 2, n, n + 2 , n + 4 Hence summing. (n - 4) + (n - 2) + n + ( n + 2) + (n + 4) = 235 5n = 235 (NB The constants add to zero) n = 235/ 5 n = 47 Hence the other four odd numbers are, 43,45,49,51
235 is a composite number because it has factors other than 1 and itself.The 4 factors of 235 are 1, 5, 47 and 235.The factor pairs of 235 are 1 * 235 and 5 * 47.The proper factors of 235 are 1, 5, and 47 or,if the definition you are using excludes 1, they are 5 and 47.The prime factors of 235 are 5 and 47.The distinct prime factors of 235 are also 5 and 47 since there is no repetition of factors.The prime factorization of 235 is: 235 = 5 * 47 .