-- If you accept decimals and fractions, then there are an infinite number of pairs that
satisfy that description.
-- If you only want to consider whole numbers, then there are only two possible pairs:
1 and 13
-1 and -13
If the sum of 2 numbers is 25 and their product is 156, the 2 numbers would be 12 and 13.
156 = 2 * 2 * 3 *13
7*13*2*2
9 x 13 = 117
9 and 13
12 and 13.
As a product of its prime factors: 2*3*13 = 78
1, 3 The above solution is wrong! 1+3=4 ok. But what about product? 1x3 = 3 and not 13. So the answer is wrong. The right answer is 2+3i and 2-3i. Of course the numbers are not real numbers but they are complex.
The numbers are 13 and 14.
3 and 13
35
To find the LCM, you multiply the numbers together and then divide by the HCF. In this case, we don't know the numbers, but we have the HCF (13) and we have the product of the numbers (1690). Thus all you do is divide 1690 by 13 to get: 1690/13 = 130 And thus the LCM of two numbers whose hcf is 13 and product is 1690 is 130.