21 and 35
To find four numbers that multiply together to equal 735, we can start by finding the prime factorization of 735, which is 3 x 5 x 7 x 7. Therefore, the four numbers are 3, 5, 7, and 7. These numbers, when multiplied together, equal 735.
3 x 5 x 7 x 7
1 x 735, 3 x 245, 5 x 147, 7 x 105, 15 x 49, 21 x 35
367.5 x 2 = 735147 x 5 = 735and so on.
To find the numbers that multiply to equal 735, we need to factorize 735 into its prime factors. 735 = 3 x 5 x 7 x 7. Therefore, the numbers that multiply to equal 735 are 3, 5, 7, and 7.
735 ÷ 4 = 183.75 Therefore, in reverse: 183.75 x 4 = 735
The highest common factor (HCF) of two numbers is the largest positive integer that divides both numbers without leaving a remainder. To find the HCF of 735 and 2625, you can use the Euclidean algorithm or prime factorization method. In this case, the prime factorization of 735 is 3 x 5 x 7^2 and the prime factorization of 2625 is 3^2 x 5^2 x 7. The common factors between the two numbers are 3 and 5, so the HCF of 735 and 2625 is 15.
Obtain the prime factors of both numbers. 450 = 2 x 3 x 3 x 5 x 5 735 = 3 x 5 x 7 x 7 The factors common to both numbers are 3 and 5. The GCF is 3 x 5 = 15
3 x 5 x 7 x 7
The prime factorization of 735 is 3 x 5 x 7 x 7 or 3*5*7^2
I assume you mean; X^2 - 72X - 735 = 0 The only way I would do this is by the quadratic formula discriminant (-72)^2 - 4(1)(-735) = 8124 and means two real roots X = - b (+/-) sqrt(b^2-4ac)/2a a = 1 b = - 72 c = - 735 X = - (-72) (+/-) sqrt[(-72)^2 - 4(1)(-735)]/2(1) X = 72 (+/-) sqrt(8124)/2 X = [72 (+/-) 2sqrt(2031)]/2 Ugly, but true.
2 x 3 x 3 x 5 x 5 = 450 3 x 5 x 7 x 7 = 735