21 and 35
To find four numbers that multiply together to equal 735, we can start by finding the prime factorization of 735, which is 3 x 5 x 7 x 7. Therefore, the four numbers are 3, 5, 7, and 7. These numbers, when multiplied together, equal 735.
3 x 5 x 7 x 7
1 x 735, 3 x 245, 5 x 147, 7 x 105, 15 x 49, 21 x 35
367.5 x 2 = 735147 x 5 = 735and so on.
To find the numbers that multiply to equal 735, we need to factorize 735 into its prime factors. 735 = 3 x 5 x 7 x 7. Therefore, the numbers that multiply to equal 735 are 3, 5, 7, and 7.
735 ÷ 4 = 183.75 Therefore, in reverse: 183.75 x 4 = 735
The highest common factor (HCF) of two numbers is the largest positive integer that divides both numbers without leaving a remainder. To find the HCF of 735 and 2625, you can use the Euclidean algorithm or prime factorization method. In this case, the prime factorization of 735 is 3 x 5 x 7^2 and the prime factorization of 2625 is 3^2 x 5^2 x 7. The common factors between the two numbers are 3 and 5, so the HCF of 735 and 2625 is 15.
The 735 times table is a multiplication table that lists the products of 735 multiplied by whole numbers. For example, the first few entries are: 735 x 1 = 735, 735 x 2 = 1470, and 735 x 3 = 2205. This table continues indefinitely, allowing for quick reference of multiples of 735. It is useful in various mathematical applications, including calculations in finance, engineering, and other fields.
Obtain the prime factors of both numbers. 450 = 2 x 3 x 3 x 5 x 5 735 = 3 x 5 x 7 x 7 The factors common to both numbers are 3 and 5. The GCF is 3 x 5 = 15
3 x 5 x 7 x 7
The prime factorization of 735 is 3 x 5 x 7 x 7 or 3*5*7^2
I assume you mean; X^2 - 72X - 735 = 0 The only way I would do this is by the quadratic formula discriminant (-72)^2 - 4(1)(-735) = 8124 and means two real roots X = - b (+/-) sqrt(b^2-4ac)/2a a = 1 b = - 72 c = - 735 X = - (-72) (+/-) sqrt[(-72)^2 - 4(1)(-735)]/2(1) X = 72 (+/-) sqrt(8124)/2 X = [72 (+/-) 2sqrt(2031)]/2 Ugly, but true.