The prime factors of 120 are 2, 3 and 5.
As a product of its prime factors: 2*2*2*3*5 = 120
The prime factors of 120 are: 2, 3, 5
To find the largest odd natural number that is a factor of 120, we first need to factorize 120 into its prime factors, which are 2^3 * 3 * 5. Since we are looking for an odd factor, we can ignore the factor of 2. The largest odd factor of 120 is then 3, as it is the largest odd prime factor present in the prime factorization of 120.
The prime factorization of 120 is not 2345 because 2345 is not a factor of 120. The prime factorization of 120 is 2^3 * 3 * 5, which means that 120 can be expressed as the product of primes 2, 3, and 5.
2 x 2 x 2 x 3 x 5 = 120
The GCF of 88, 96, 120 is 8. The prime factorization of 88 is 2*2*2*11 The prime factorization of 96 is 2*2*2*2*2*3 The prime factorization of 120 is 2*2*2*3*5 The GCF is 2*2*2 = 8.
A prime factor cannot be a multiple of anything (other than 1).
120 = 2 * 2 * 2 * 3 * 5 Written as a product of powers is (2^3) * 3 * 5
30 is 2*3*5. 120 is 2^3*3*5. As all the prime factors of 120 appear with a smaller or equal multiplicity in 30, 30 is a factor of 120.
prime factor, 5
The prime factors of 100 are 2, 2, 5, and 5. The prime factors of 120 are 2, 2, 2, 3, and 5. The prime factors of 180 are 2, 2, 3, 3, and 5. The prime factors that all three numbers have in common are 2, 2, and 5. Therefore, the greatest common factor is 2 x 2 x 5 = 20.
The prime factor of 2 is 2.