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If the sum of its' digits are divisible by 3 for all numbers greater than 9.
U={whole number greater than 10 but smaller than 30 } X={numbers divisible by 3 } Y Odd numbers
Three of them.
There is only one number that can be divisible by both 3 and 4 yet not greater than 20, 12.
Because many of them are divisible by smaller odd numbers. For example 35 is divisible by 5 and so 35 cannot be a prime number.
U={whole number greater than 10 but smaller than 30 } X={numbers divisible by 3 } Y Odd numbers
If the sum of its' digits are divisible by 3 for all numbers greater than 9.
402. It is the first number after 400 for which the digital root (the sum of its digits) is divisible by 3. The digital root being divisible by 3 is a test for divisibility by 3.
78,84,90,96
Three of them.
There is only one number that can be divisible by both 3 and 4 yet not greater than 20, 12.
The numbers divisible by 3 are 3,6,9,12,15,18,21,24,27,30,33.....
Because many of them are divisible by smaller odd numbers. For example 35 is divisible by 5 and so 35 cannot be a prime number.
7x3 = 21 All numbers from 1-400 (399 total) that are factors of 21: 399/21 = 19
All numbers divisible by 3 are NOT divisible by 9. As an example, 6, which is divisible by 3, is not divisible by 9. However, all numbers divisible by 9 are also divisible by 3 because 9 is divisible by 3.
Yes; all numbers that are divisible by 9 are divisible by 3.
9 is greater than 6 and divisible by 3.