Q: What are M and Y if Y plus y plus y plus equals MY?

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using normal algebraic methods, all I can get is m=0 and y=all numbers

x = (y-b)/m

If y = mx + b, then x = (y-b)/m (for m not equal to zero).

4y

m

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using normal algebraic methods, all I can get is m=0 and y=all numbers

y-b/x=m

the answer is: (y-b)/x = m y = mx + b y - b = mx (y-b)/x = m

x = (y-b)/m

If y = mx + b, then x = (y-b)/m (for m not equal to zero).

m = slope of the line. b = the Y intercept.

well, m is the slope and c is the y-intercept

Y = mX + 6 Y - 6 = mX (Y - 6)/X = m ==============If you had values you could get the integer that is m

4y

m

The slope and y intercept which are m and b respectively.

For the equation y = 3x + 3, the value of m (the slope) is 3.