M=3 because y+y+y= 3xY and MY= MxY
using normal algebraic methods, all I can get is m=0 and y=all numbers
x = (y-b)/m
If y = mx + b, then x = (y-b)/m (for m not equal to zero).
4y
m
using normal algebraic methods, all I can get is m=0 and y=all numbers
y-b/x=m
x = (y-b)/m
the answer is: (y-b)/x = m y = mx + b y - b = mx (y-b)/x = m
If y = mx + b, then x = (y-b)/m (for m not equal to zero).
well, m is the slope and c is the y-intercept
m = slope of the line. b = the Y intercept.
Y = mX + 6 Y - 6 = mX (Y - 6)/X = m ==============If you had values you could get the integer that is m
4y
m
The slope and y intercept which are m and b respectively.
a = 3 and y = 0