12410
There are 8 divisors of 105 (viz: 1, 3, 5, 7, 15, 21, 35, 105)
To find how many two-digit numbers ( n ) result in a remainder of 4 when dividing 109, we can express this mathematically as ( 109 \equiv 4 \mod n ). This simplifies to ( 109 - 4 = 105 ) being divisible by ( n ), or ( n ) being a divisor of 105. The divisors of 105 that are two-digit numbers are 15, 21, 35, and 105, giving us a total of 4 two-digit divisors.
1, 2, 3, 5, 7, 10, 14, 15, 21, 30, 42, 70, 105, 210
The divisors of 735 are 1, 3, 5, 7, 15, 21, 35, 49, 105, 147, 245, and 735.
Divisors are used to divide numbers.
2,4,8 (1 and 16 are divisors too, but the number and 1 are always divisors)
The divisors of 105 are 1, 3, 5, 7, 15, 21, 35, and 105.Multiples of 105 would be any number divided by 105 which yield an integer (this means it equates to a whole number - no remainders.)I assume what was meant were the divisors and not the multiples of 105, since the multiples can be easily obtained by just multiplying 105 by a list of integers -> 105, 210, 315, 420, and so forth. The multiples of 105 is an infinitely long list. (Negatives also count in this list.)105, 210, 315, 420, 525 and so on!
The divisors of 41231 are: 1, 41231.
12 has six divisors.
136 has eight divisors.
The divisors of 66 are 1,2,3,6,11,22,33 and 66.
The divisors of 79 are: 1, 79.