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Q: What are all of the divisors of 24?

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60

Sum of 24's divisors: 60.

600 has 24 divisors.

The divisors of 24 are: 1, 2, 3, 4, 6, 8, 12, 24.

24 of them.

1,2,3,4,6,8,12,24

24 (1,2,3,4,6,8,12 & 24)

1, 2, 3, 4, 6, 8, 12, 24 (sum = 60)

360

Multiples: 12, 24, 36. Divisors: 1 2 3.

Prime divisors of 120 = 2, 4, 8, 3, 24, 5

6

The divisors of 16 are 2, 4 and 8. The divisors of 24 are 2, 3, 4, 8 and 12. Hence the GCD is 8.

The divisors of 16 are 2, 4 and 8. The divisors of 24 are 2, 3, 4, 8 and 12. Hence the GCD is 8.

The divisors of 48 are: 1, 2, 3, 4, 6, 8, 12, 16, 24, 48.

1; 2; 3; 4; 6; 8; 12; 24 :]

24 of them.

The divisors of 39 are 1, 3, 13, and 39

The divisors of 55 are 1, 5, 11, 55.

Technically, all numbers (except zero) will go into 24. (For example, the number -2.5 will go into 24 exactly -9.6 times. [24 ÷ -2.5 = -9.6]) However, if you would like to narrow this down a bit and include only whole numbers above zero (between 1 and 24), then you are asking for the "factors" or "divisors" of 24. The set of all positive divisors of 24 are: 1, 2, 3, 4, 6, 8, 12, 24

0.28235294117647

The positive divisors of 48 are: 1, 2, 3, 4, 6, 8, 12, 16, 24, 48.

The divisors of 96 are: 1, 2, 3, 4, 6, 8, 12, 16, 24, 32, 48, 96.

Common divisors of 16 and 24 are 1, 2, 4, 8.

14 is deficient. It is less than the sum of it's divisors. In mathematics, a deficient number or defective number is a number n for which σ(n) < 2n. Here σ(n) is the sum-of-divisors function: the sum of all positive divisors of n, including n itself Proof.. divisors of 14 are 1,2, and 7 and 14. Now, 2n=28 and and the sum the all the divisors including 14 is 24<28