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There are 8 possible numbers.

The last digit can be 1 or 7 since the number is odd.

The first digit can be any of the three except 0 since then it would not

be a 4 digit number, but once you pick the last digit, there are really only 2 numbers left for the first digit.

So let's use 1 as the last digit

the numbers are

7401, 7041, 4701, 4071.

Now use 7 as the last digit.

We have 1407, 1047, 4107, 4017.

So the 8 numbers are:

7401, 7041, 4701, 4071,1407, 1047, 4107, 4017

( the number of possible numbers is 8 since that is 23 . There are 2 choices for

the last digit, the once we pick that 2 choices for the first digit. For either of the remaining two digits there are 2 choices and then the last digit is fixed.)

Q: What are all of the possible odd 4 digit number using 1 4 7 0?

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1111, unless you allow negative number. In that case, the answer is -9999.

Total number of possible 3-digit numbers = 9!x10!10!

10 because 10 is the first 2 digit number out of all numbers.

88,888

If repeated digits are allowed, then the largest 12-digit number is 999,999,999,999 .If repeated digits are not allowed, then the largest 12-digit number is 989,898,989,898 .If the same digit can't be used more than once, then the largest possible number has only10 digits. The number is 9,876,543,210 .

Related questions

The sum is 154.

1111, unless you allow negative number. In that case, the answer is -9999.

I would not like a list all possible 4 digit combination using 0-9.

1,000,000 or, if they need to be different, then 1,023,456.

Total number of possible 3-digit numbers = 9!x10!10!

All nines 9,999,999,999

10 because 10 is the first 2 digit number out of all numbers.

All 9's.

88,888

If repeated digits are allowed, then the largest 12-digit number is 999,999,999,999 .If repeated digits are not allowed, then the largest 12-digit number is 989,898,989,898 .If the same digit can't be used more than once, then the largest possible number has only10 digits. The number is 9,876,543,210 .

5,040Assuming that the combination uses ALL single digits from 0 to 9, then for the first digit you will be able to use all 10 numbers, for the second digit you will be able to use 9, for the third digit 8 and for the last digit 7, giving a total number of combinations of 10 x 9 x 8 x 7 = 5,040 without the same number being used more than once in each combination.

i would like a list all possible 4 digit combination using 0-9