answersLogoWhite

0


Best Answer

There are 8 possible numbers.

The last digit can be 1 or 7 since the number is odd.

The first digit can be any of the three except 0 since then it would not

be a 4 digit number, but once you pick the last digit, there are really only 2 numbers left for the first digit.

So let's use 1 as the last digit

the numbers are

7401, 7041, 4701, 4071.

Now use 7 as the last digit.

We have 1407, 1047, 4107, 4017.

So the 8 numbers are:

7401, 7041, 4701, 4071,1407, 1047, 4107, 4017

( the number of possible numbers is 8 since that is 23 . There are 2 choices for

the last digit, the once we pick that 2 choices for the first digit. For either of the remaining two digits there are 2 choices and then the last digit is fixed.)

User Avatar

Wiki User

13y ago
This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: What are all of the possible odd 4 digit number using 1 4 7 0?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Related questions

What is the sum of all possible 2 digit number using the digits 3 and 4?

The sum is 154.


What is the least possible four digit number using all the digits repeated?

1111, unless you allow negative number. In that case, the answer is -9999.


You would like a list all possible 4 digit combination using 0-9?

I would not like a list all possible 4 digit combination using 0-9.


What is the least possible 7 digit can be formed using all the digit?

1,000,000 or, if they need to be different, then 1,023,456.


What are all possible three digit numbers using numbers 0-1-2-3-4-5-6-7-8-9?

Total number of possible 3-digit numbers = 9!x10!10!


What is the greatest possible 10 digit number?

All nines 9,999,999,999


What is the least product possible when you multiply a 1 digit number greater than 0 by a 2 digit number?

10 because 10 is the first 2 digit number out of all numbers.


What is the largest possible 9-digit whole number?

All 9's.


Largest 5 digit number using all even numbers?

88,888


The largest 12- digit number where repeated digits are allowed?

If repeated digits are allowed, then the largest 12-digit number is 999,999,999,999 .If repeated digits are not allowed, then the largest 12-digit number is 989,898,989,898 .If the same digit can't be used more than once, then the largest possible number has only10 digits. The number is 9,876,543,210 .


How many possible 4 digit combinations are possible without using the same number more than once?

5,040Assuming that the combination uses ALL single digits from 0 to 9, then for the first digit you will be able to use all 10 numbers, for the second digit you will be able to use 9, for the third digit 8 and for the last digit 7, giving a total number of combinations of 10 x 9 x 8 x 7 = 5,040 without the same number being used more than once in each combination.


What are the combinations of 4-digit code of 0-9 and a-z?

i would like a list all possible 4 digit combination using 0-9