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How many 3 digit numbers can be made from 0123456789?
To form a three-digit number using the digits 0-9, the first digit cannot be 0 (as it would not be a three-digit number). Thus, the first digit can be any of the digits from 1 to 9 (9 options). The second and third digits can each be any digit from 0 to 9 (10 options each). Therefore, the total number of three-digit numbers is (9 \times 10 \times 10 = 900).
How many three-digit area codes are possible if the first digit cannot be a 0?
There are 900 possible three-digit numbers not beginning with 0. (Note, however, that this question does not accurately describe the restrictions on numbers that can be used as area codes.)
How many three digit numbers are possible if the left digit cannot be zero?
a lot * * * * * Possibly, though that answer is relative. The correct answer is 900.
How many different three digit numbers can you form using the digits 2 5 and 7?
6 possible 3 digit combonations
How many 3 digit numbers are possible from the digits 0123456789?
Let's solve it a step at a time. For the first digit, how many choices do you have? 9 You can choose 1..9 but not 0, so that's nine choices for the most significant digit. For the second digit, how many choices do you have? 10 It can be 0..9. For the third digit, you also have 10 choices. Choosing one digit doesn't limit your choices for other digits and mirrored numbers (e.g. 123 and 321) are different, so all choices make a unique number. So the total is the product of our three choices: 9x10x10
