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4 6 8 9 10 12 14 15 16 18 20 21 22 24 25 26 27 28 30 32 33 34 35 36 38 39 40 42 44 45 46 48 49 50 51 52 54 55 56 57 58 60 62 63 64 65 66 68 69 70 72 74 75 76 77 78 80 81 82 84 85 86 87 88 90 91 92 93 94 95 96 98 99 100

Q: What are all the composites n umbers from 1-100?

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No, if you think that you have it, you can always find one that is larger. Take, for example you find an even composite number (all even numbers, except 2 - which is the only even prime, are composite). Call this number N. Now add 2 to N for N+2, which is also even, so it is also a composite. What about odd composites: if you find an odd composite(M), then add 1 to it: odd+odd=even, so M+1 is even, which is also composite. You can keep going forever.

its 5035the summarian notation tells you that(sum of all #from 0 to a number'N'(sum of all #from 0 to N) = (n)+(n-1)+(n-2)+(n-3)+...+(2) +(1) or(sum of all #from 0 to N) = (1)+ (2) + (3) + (4)+...+(n-1)+(n)the two different sums are aligned by columns. now add the two colunms accordingly and you'll get2x(sum of all #from 0 to N)=(n+1)+(n+1)+...+(n+1) (n+1)is added n timesso2x(sum of all #from 0 to N) =n(n+1)(sum of all #from 0 to N) =n(n+1)/2so (sum of 5 to 100) = (sum of 0 to 100)- (sum of 0 to 5)=100(101)/2 - 5(6)/2 = 5050 - 15 = 5035

For any number n, n + 0 = 0 + n = n All you need to do is to substitute any number of your choice, for n.

Since n! is the product of all the numbers from 1 through n and (n+1)! is everything in n! multiplied by n+1, the quotient is n+1 ■

N = 3. That really is all there is to it.

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if the serial number ends in n or x

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Let's form the proportion: 0.6/1.1 = n/8.47 or (6/10)/(11/10) = (n/1)/(847/100) (6/10)(10/11) = (n/1)(100/847) 6/11 = 100n/847 Proportion is a statement that two ratios are equal. The value of n makes this proportion true. The numbers that form a proportion are called the term of proportion. There is a special relationship between the terms, called the cross products property. That is, 6/11 = 100n/847 (6)(847) = (11)(100n) 5082 = 1100n so, n must be a number that when multiply 1100 equals 5082. 5082/1100 = (1100/1100)n 4.62 = n So, the proportion is: 6/11 = [100(4.62)]/847 6/11 = 462/847 Or, If you look at 847, you see that 11 x 77 = 847. So 100n must equals 6 x 77 = 462, in order to make the proportion true. So, 100n = 462 n = 4.62 and 100 x 4.62 = 462. Thus the proportion is: 6/11 = 462/847 If you want the original proportion is, 0.6/1.1 = 4.62/8.47

No, if you think that you have it, you can always find one that is larger. Take, for example you find an even composite number (all even numbers, except 2 - which is the only even prime, are composite). Call this number N. Now add 2 to N for N+2, which is also even, so it is also a composite. What about odd composites: if you find an odd composite(M), then add 1 to it: odd+odd=even, so M+1 is even, which is also composite. You can keep going forever.

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