its 5035
the summarian notation tells you that
(sum of all #from 0 to a number'N'
(sum of all #from 0 to N) = (n)+(n-1)+(n-2)+(n-3)+...+(2) +(1) or
(sum of all #from 0 to N) = (1)+ (2) + (3) + (4)+...+(n-1)+(n)
the two different sums are aligned by columns. now add the two colunms accordingly and you'll get
2x(sum of all #from 0 to N)=(n+1)+(n+1)+...+(n+1) (n+1)is added n times
so
2x(sum of all #from 0 to N) =n(n+1)
(sum of all #from 0 to N) =n(n+1)/2
so (sum of 5 to 100) = (sum of 0 to 100)- (sum of 0 to 5)
=100(101)/2 - 5(6)/2 = 5050 - 15 = 5035
It is instructive to note that you can rewrite 1+2+3+4....+99+100 as 1+100+2+99+3+98....+50+51 Then you can group each pair of numbers as (1+100)+(2+99)+(3+98)+...+(50+51) All of these couplets add up to 101, and there are 50 of them. Thus the sum of the first 100 whole numbers is 50x101. This can be calculated at 5,050.
5050 i think
Add them up.
3 pairs of whole numbers add up to 7: 1 +6, 2+5, 3+4 (0+7 also equals 7, but zero is not a whole number)
If its sequential, and whole numbers, find the median, in this case 50.5 then times it by the largest number which is 100, so 50.5 * 100 = 5050Take 2:Multiply by number of numbers, not largest numberWhole numbers, rising in equal increments, eg 1,2,3 or 6,8,10 etc.Find the median then multiply by number of numbers.Example: sum of 6,7,8,9,10,11 median is 8.5 and there are 6 numbersSo: 8.5 * 6 = 51Example:sum of 21,24,27,30,33,36,39 median is 30 and there are 7 numbersSo: 30 * 7 = 210
Depending on how you look at it, there are either 99 or 100 whole numbers up to 100. If you mean up to and including 100, then the answer is 100 whole numbers, if not, then the answer is 99 whole numbers.
It is instructive to note that you can rewrite 1+2+3+4....+99+100 as 1+100+2+99+3+98....+50+51 Then you can group each pair of numbers as (1+100)+(2+99)+(3+98)+...+(50+51) All of these couplets add up to 101, and there are 50 of them. Thus the sum of the first 100 whole numbers is 50x101. This can be calculated at 5,050.
5050 i think
There are no four consecutive whole numbers that add up to 35. The sum of two consecutive [whole] numbers is an even number plus an odd number which is an odd number. The sum of two consecutive numbers and the two next consecutive numbers is the sum of two odd numbers which is even, but 35 is odd, so no four consecutive whole numbers cannot add up to 35.
Well, isn't that a happy little math problem? Let's see, if we take 22, 23, and 24, and add them together, we get 69, just one more than 68. So, let's adjust slightly and take 21, 22, and 23 instead. When we add those up, we get a perfect total of 66. Just a couple numbers off from 68, but that's the joy of math - we can always make small adjustments to find the right answer.
There is no set of 8 consecutive whole numbers whose sum is 75.
No 5 odd numbers add up to 100. The sum of any two odd numbers is even. The sum of any two even numbers is even. So the sum of any 4 odd numbers must be even. Take that and add an odd number and the sum must be odd. Therefore, the sum of any 5 odd numbers must be odd. 100 is even. In conclusion: The sum of any odd number of odd numbers is odd.
Add them up.
2 mixed numbers can only be a whole when the 2 numerators add up to the number
The sum of the first n positive integers can be calculated using the formula n(n+1)/2. In this case, n=100, so the sum of the first 100 positive integers is 100(100+1)/2 = 100(101)/2 = 5050.
Consecutive whole numbers will have an odd sum. Consecutive odd numbers, or consecutive prime numbers, will be 29 and 31.
When the fractional parts, if any, of the two decimal numbers sum to 1.